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grigory [225]
4 years ago
12

Which of these structure represent a soap? a. CH3CO2-K+ b. CH3(CH2)14CO2-NA+. c. CH3(CH2)12COOH. d.CH3(CH2)7CO2(CH2)7NA

Chemistry
1 answer:
levacccp [35]4 years ago
7 0
I  think the correct answer from the choices listed above is option B. It would be CH3(CH2)14CO2-NA+ that would represent the structure of a soap. A soap<span> is a </span>salt<span> of a </span>fatty acid. <span>Soaps for cleaning are obtained by treating vegetable or animal oils and fats with a strong </span>base<span>, such as </span>sodium hydroxide<span> or </span>potassium hydroxide<span> in an </span>aqueous<span> solution.</span>
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Given that the concentration of myosin is 25pmol·L−1 and Rmax(Vmax)=208pmol·L−1·s−1 , determine the turnover number of the enzym
DedPeter [7]

Answer:

8.32 s⁻¹

Explanation:

Given that:

The concentration of myosin = 25 pmol/L

R_max = 208 pmol/L/s

The objective is to determine the  turnover number of the enzyme molecule myosin, which has a single active site.

In a single active site of enzyme is known to be a region where there is binding of between substrate molecules, thereafter undergoing chemical reaction.

The turnover number of the enzyme is said to be the number of these substrate molecule which binds together are being converted into products.

The turnover number of the enzyme molecule of myosin can be calculated by the expression: \dfrac{R_{max}}{concentration}

⇒ \dfrac{208 pmol/L/s}{25 pmol/L}

= 8.32 s⁻¹

4 0
4 years ago
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Serggg [28]

4Fe+3O₂⇒2Fe₂O₃

CO₂+2Cl₂⇒O₂+CCl₄

<h3>Further explanation  </h3>

Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:  

1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.  

2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product  

3. Select the coefficient of the substance with the most complex chemical formula equal to 1  

For simple equations, you can experiment with the balance of the number of atoms on the left and right

4Fe+3O₂⇒2Fe₂O₃

CO₂+2Cl₂⇒O₂+CCl₄

  • with variable :

aFe+bO₂⇒Fe₂O₃

Fe , left=a, right=2⇒a=2

O, left=2b, right=3⇒2b=3⇒b=3/2

the equation :

2Fe+3/2O₂⇒Fe₂O₃   x2

4Fe+3O₂⇒2Fe₂O₃

aCO₂+bCl₂⇒O₂+CCl₄

C, left=a, right=1⇒a=1

Cl, left=2b, right=4⇒b=2

O, left=2a, right=2⇒2a=2⇒a=1

the equation :

CO₂+2Cl₂⇒O₂+CCl₄

8 0
3 years ago
10 uses of metals in daily life
Lesechka [4]

Answer:For jewellery and ornaments, gold, platinum and silver are being used.


For building purposes, iron and steel can be used.Iron and aluminium are used as utensils.

The thermometer uses mercury and helps to monitor the temperature.

The insulation wires are made of aluminium.

Aluminium foils are being used as wrappers for food.In sweets, a silver foil is being used.

To avoid rusting, zinc is used for galvanizing.In vehicles, iron is being used.

For making cable wires, copper is being used.

Explanation:

6 0
2 years ago
Read 2 more answers
What does a base release when it is placed in water?
Alexxx [7]

Answer:

D - Hydroxide Ion (OH-)

Explanation:

A base provides either hydroxide ions (OH–) or other negatively charged ions that combine with hydrogen ions, reducing their concentration in the solution and thereby raising the pH. In cases where the base releases hydroxide ions, these ions bind to free hydrogen ions, generating new water molecules.

3 0
3 years ago
The plot shows the absorbance spectra for solutions of caffeine, benzoic acid, and Mountain Dew® soda, each in 0.010 M HCl . A p
Aliun [14]

Complete Question

The diagram of the complete question is shown on the first uploaded image.

Answer:

a) The approximate absorbance of benzoic acid at 228 nm? : A = 0.8

b) The molar absorptivity(∈)

of benzoic acid at 228 nm? : ∈   =  1.12 * 10^{4} M^{-1} cm^{-1}

Explanation:

Looking at the absorbance spectra, we can see that the approximate absorbance of benzoic acid at 228 is 0.8.

mass concentration of benzoic acid = 8.74 \frac{mg}{L} =8.74 * 10^{-3} \frac{g}{L}

the molar concentration of benzoic acid = (mass concentration of benzoic acid) / (molar mass of benzoic acid )

 

molar concentration of benzoic acid = (8.74 *10^{-3} \frac{g}{L} ) /(122.12\frac{g}{mol} )

molar concentration of benzoic acid = 7.157 * 10^{-5}M

molar absorptivity (∈) of benzoic acid = (absorbance) /[ (molar concentration of benzoic acid ) × (path length) ]

 

 ∈    = (0.8) / [ (7.157 *10^{-5}M) ×(1.00 cm)]

        =  1.12 * 10^{4} M^{-1} cm^{-1}

     

5 0
3 years ago
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