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Leni [432]
1 year ago
13

I need some help with crush advise. So basically i have a crush on this dude but i don't think he know me we are not in the same

class but we see each other at morning time and recess by the way he is Vietnamese and he is cute. If you have some advice. ( PLEASE TELL ME) please don't just steal the points, really help me out
Chemistry
2 answers:
Maru [420]1 year ago
8 0

Answer:

Go for it!

Explanation:

You only live once, seriously just go up and talk to him. Say something like, "Hey, you seemed cool I just wanted to say hi. Do you have an ig?" :) you won't regret it.

EleoNora [17]1 year ago
7 0

Answer:

There are a couple of things you should do! first, you should become his friend, and be a good friend, too. Don't fl!rt with him when you first meet, or in the first couple of times you guys meet. Ask him things you are genuinely curious to know about him, don't ask generic questions such as " whats your favorite color" or make small talk. Ask him things that relate to him more like what's his full name, or where is he from. If you really are curious to know what his favorite color is, you can ask him, but make sure he knows you are genuinely curious to know, and not just making small talk. After getting to know him better, you have to ask yourself if you are still interested in him in "that" way, or interested at all, even. If the answer is yes, you still have love interest the next thing you should know is if he is single, or likes someone. When you ask him if hes single don't make it weird if he says no, just be chill. If he is single, but has a crush on someone you should ask him who. If he doesn't tell you and you guys are close already, it's probably you. After finding out all these things about him, you should wait about 2 months and then confess to him that you like him (if he has not already confessed to you) and no worries if he rejects you, rejection happens sometimes and it's totally okay. It may not feel like it right away, or even longer away but you  will eventually get over him.

Explanation:

I hope these tips were helpful, and if you have any more questions please ask I'm here to help you <3

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How to find molecular weight​
Nastasia [14]

Answer:

Using the periodic table of the elements to find atomic weights, we find that hydrogen has an atomic weight of 1, and oxygen's is 16. In order to calculate the molecular weight of one water molecule, we add the contributions from each atom; that is, 2(1) + 1(16) = 18 grams/mole.

Explanation:

hope this helped

3 0
3 years ago
The Olympian swam 200 meters in 20 seconds. <br> 1) velocity<br> 2) acceleration<br> 3) speed
irakobra [83]

Answer: velocity

Explanation:

3 0
3 years ago
Read 2 more answers
Which statement below correctly describes the relationship between Q and K for both reactions? Are these reactions spontaneous a
nikklg [1K]

Answer:

Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.

Explanation:

Hello,

In this case, the undergoing chemical reactions with their proper Gibbs free energy of reaction are:

A->B;\Delta _rG^o=-13 kJ/mol

C ->D ;\Delta _rG^o=3.5 kJ/mol

The cellular concentrations are as follows: [A] = 0.050 mM, [B] = 4.0 mM, [C] = 0.060 mM and [D] = 0.010 mM.

For each case, the reaction quotient is:

Q_1=\frac{4.0mM}{0.050mM}=80\\ Q_2=\frac{0.010mM}{0.060mM}=0.167

A typical temperature at a cell is about 30°C, in such a way, the equilibrium constants are:

K_1=exp(-\frac{-13000J/mol}{8.314J/mol*K*303.15K} )=173.8\\K_2=exp(-\frac{3500J/mol}{8.314J/mol*K*303.15K} )=0.249

Therefore, Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.

Best regards.

6 0
3 years ago
Find the boiling point temperature at 760 torr of an isomer of octane, c8h18, if its enthalpy of vaporization is 38,210 j mol-1
mixas84 [53]

According to Clausius-Clayperon equation,

ln(\frac{P_{1} }{P_{2} }) = \frac{delta H_{vap} }{R} (\frac{1}{T_{2} }-\frac{1}{T_{1} }   )

P_{1}is the vapor pressure at boiling point = 760 torr

P_{2} is the vapor pressure at T_{2} =638.43 torr

TemperatureT_{2} = 110.0^{0}C + 273 = 383 K

ΔH_{vap} = 38210 J/mol

Plugging in the values, we get

ln(\frac{P_{1} }{P_{2} }) = \frac{delta H_{vap} }{R} (\frac{1}{T_{2} }-\frac{1}{T_{1} }   )

ln\frac{760 torr}{638.43 torr} =\frac{38210 J/mol}{8.314 J/(mol.K)} (\frac{1}{383 K}-\frac{1}{T_{1} }

T_{1} = 389 K

Therefore, the boiling point of octane = 389 K - 273 = 116^{0}C

7 0
3 years ago
Convert the following to Fahrenheit
jeka94

Explanation:

1. 50°F

2. 86°F

3.104°F

4. 98.6°F

5. 32°F

Here is the formula

T(°F) = T(°C) × 9/5 + 32

or

T(°F) = T(°C) × 1.8 + 32

Hope it helps...

4 0
3 years ago
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