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Leni [432]
10 months ago
13

I need some help with crush advise. So basically i have a crush on this dude but i don't think he know me we are not in the same

class but we see each other at morning time and recess by the way he is Vietnamese and he is cute. If you have some advice. ( PLEASE TELL ME) please don't just steal the points, really help me out
Chemistry
2 answers:
Maru [420]10 months ago
8 0

Answer:

Go for it!

Explanation:

You only live once, seriously just go up and talk to him. Say something like, "Hey, you seemed cool I just wanted to say hi. Do you have an ig?" :) you won't regret it.

EleoNora [17]10 months ago
7 0

Answer:

There are a couple of things you should do! first, you should become his friend, and be a good friend, too. Don't fl!rt with him when you first meet, or in the first couple of times you guys meet. Ask him things you are genuinely curious to know about him, don't ask generic questions such as " whats your favorite color" or make small talk. Ask him things that relate to him more like what's his full name, or where is he from. If you really are curious to know what his favorite color is, you can ask him, but make sure he knows you are genuinely curious to know, and not just making small talk. After getting to know him better, you have to ask yourself if you are still interested in him in "that" way, or interested at all, even. If the answer is yes, you still have love interest the next thing you should know is if he is single, or likes someone. When you ask him if hes single don't make it weird if he says no, just be chill. If he is single, but has a crush on someone you should ask him who. If he doesn't tell you and you guys are close already, it's probably you. After finding out all these things about him, you should wait about 2 months and then confess to him that you like him (if he has not already confessed to you) and no worries if he rejects you, rejection happens sometimes and it's totally okay. It may not feel like it right away, or even longer away but you  will eventually get over him.

Explanation:

I hope these tips were helpful, and if you have any more questions please ask I'm here to help you <3

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What mass of CaSO3 must have been present initially to produce 14.5 L of SO2 gas at a temperature of 12.5°C and a pressure of 1.
german
When the reaction equation is:

CaSO3(s) → CaO(s) + SO2(g)

we can see that the molar ratio between CaSO3 & SO2 is 1:1 so, we need to find first the moles SO2.

to get the moles of SO2 we are going to use the ideal gas equation:

PV = nRT

when P is the pressure =  1.1 atm

and V is the volume = 14.5 L 

n is the moles' number (which we need to calculate)

R ideal gas constant = 0.0821

and T is the temperature in Kelvin = 12.5 + 273 = 285.5 K

so, by substitution:

1.1 * 14.5 L = n * 0.0821 * 285.5

∴ n = 1.1 * 14.5 / (0.0821*285.5)

       = 0.68 moles SO2

∴ moles CaSO3 = 0.68 moles

so we can easily get the mass of CaSO3:

when mass = moles * molar mass

and we know that the molar mass of CaSO3= 40 + 32 + 16 * 3 = 120 g/mol


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7 0
3 years ago
A solution contains an unknown amount of dissolved magnesium. Addition of
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Taking into account the reaction stoichiometry, 2.13 grams of magnesium was dissolved in the solution.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Mg²⁺(aq) + Na₂CO₃(aq) → MgCO₃(s) + 2 Na⁺(aq)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Mg²⁺: 1 mole
  • Na₂CO₃: 1  mole
  • MgCO₃: 1 mole
  • Na⁺: 2 moles

The molar mass of the compounds is:

  • Mg²⁺: 24.3 g/mole
  • Na₂CO₃: 106 g/mole
  • MgCO₃: 84.3 g/mole
  • Na⁺: 23 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Mg²⁺: 1 mole ×24.3 g/mole= 24.3 grams
  • Na₂CO₃: 1 mole ×106 g/mole= 106 grams
  • MgCO₃: 1 mole ×84.3 g/mole=84.3 grams
  • Na⁺: 2 moles ×23 g/mole= 46 grams

<h3>Mass of magnesium dissolved</h3>

The following rule of three can be applied: If by reaction stoichiometry 1 mole of Na₂CO₃ react with 24.3 grams of magnesium, 0.0877 moles of Na₂CO₃ react with how much mass of magnesium?

mass of magnesium=\frac{0.0877 moles of Na_{2}C O_{3}x24.3 grams of magnesium }{1 mole of Na_{2}C O_{3}}

<u><em>mass of magnesium= 2.13 grams</em></u>

Finally, 2.13 grams of magnesium was dissolved in the solution.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

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