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3 years ago

6

How do you determine the limit algebraically?

1 answer:

eduard3 years ago

5 0

Answer:

0.125

Step-by-step explanation:

This is a standard calculus question. If you search out L'Hopital's Rule you will find that there are only Calculus examples present. If you use calculus, the answer comes to 1/8. The only way I can think of doing this without the use of Calculus is to let x = something very small -- say x = 0.0001 That approaches 0, but it is not quite = to 0.

So let's try it.

16 + 0.00001 = 16.00001

sqrt(16.0001) = 4.00000125

Now subtract 4

4.00000125 - 4

0.00000125

Now divide by 0.00001

0.12499998

which is close to 0.125.

If someone else can give you an answer that is "purer" than this one, take it.

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Step-by-step explanation:

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3 years ago

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A standardized exam's scores are normally distributed. In a recent year, the mean test score was 14901490 and the standard dev

kicyunya [14]

<h2>Answer with explanation:</h2>

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Standard deviation : $\sigma=320$

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z-score : $z=\dfrac{x-\mu}{\sigma}$

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3 years ago

3x + 5y=32 2x + 3y=23 solve by elimintaion method

algol [13]

Answer:

x=19, y=-5

Step-by-step explanation:

Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.

Point Form:

(19, -5)

Equation Form:

x=19, y=-5

Hope this helps.

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3 years ago