How do you determine the limit algebraically?
1 answer:
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Eighteen hundredths as a decimal is 0.18
<h3><u>Solution:</u></h3>We have to find eighteen hundredths as a decimal
Eighteen hundredths means 18 over one hundred
We have to write 18 over one hundred as decimal
A decimal is a fraction written in a special form
Let us first write 18 over one hundred in fraction form
Eighteen hundredths = 18 over one hundred
Now divide 18 by 100 to get the decimal form
Thus the eighteen hundredths as a decimal is 0.18
The factoring of the expression x²=-x+6 is (x-2)(x+3)
By ordering the values, we get:
x² + x - 6 = 0
To solve this exercise, we have to follow the rules of factoring:
1. Looking for the a and b number that state the following equations:
- a + b = 1
- a * b = - 6
Analyzing that (a*b) is a negative number, it means that (a) and (b) have different signs, and due to the results of (a+b) is positive the higher number has to be the positive one.
The number could be:
a = -2
b = 3
Confirming:
a + b = -2 + 3 = 1
a * b = (-2) * 3 = - 6
2. Rewriting the factored expression (x+a)(x+b) with the obtained values, we get:
(x-2)(x+3)
<h3>What is factoring?</h3>Is a technique that consist of decomposition of a factor into a product of another factor, which when multiplied together give the original number.
Learn more about factoring at brainly.com/question/24734894
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