How do you determine the limit algebraically?
1 answer:
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Answer:
7.
8. l=11cm and w=7 cm
9.
10.
Step-by-step explanation:
Question 7.
The given expression is:
Expand the parenthesis using the distributive property:
Group similar terms:
Simplify
Divide both sides by -10
Question 8:
Let the width of the rectangle be;
The length of the rectangle is
The perimeter is given as:
Given that the perimeter P=36, then:
Divide both sides by 2:
Subtract 4 from both sides:
The dimensions of the rectangle is: w=7 cm and l=7+4=11cm
Question 9
Let the number be x.
"5 fewer than the number" is written as
"5 fewer than a number is at least 12" becomes
Question 10:
Let the number be x.
The quotient of a number and 3 is written as:
The quotient of a number and 3 is no more than 15 is written as;
Answer:
The third choice is the one you want
Step-by-step explanation:
If we are to write the equation of a line perpendicular to WX, we first must determine what the slope of the WX is, because the line perpendicular to WX has a slope that is the flip of the slope of WX with the opposite sign. Solving for y takes care of finding the slope of WX:
2x + y = -5 so
y = -2x - 5
The slope is -2. That means that the reciprocal slope is 1/2. Using that slope along with the coordinates x = -1 and y = -2, we first write the line using point-slope form and then solve it for y. Start by filling in the m, the x value and the y value:
Getting rid of the double negatives gives us:
Distributing then gives us:
And finally solving for y (I am going to express the 2 on the left as 4/2 when I move it by subtraction in order to add those fractions):
And the final equation in slope-intercept form is: