When two balanced dice are rolled, the sum of the dice can be 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, or 12, giving 11 possibilities. th
RUDIKE [14]
False.
There are 36 possible outcomes, corresponding to numbers 1-6 independently appearing on each of the dice. Only one of those outcomes is double-sixes, resulting in a sum of 12. The probability that the sum is 12 is 1/36.
In short, the 11 outcomes listed in your problem statement are not equally-likely.
Answer:
2A /h = b
Step-by-step explanation:
A=1/2bh
Multiply each side by 2
2A = 2*1/2bh
2A = bh
Divide each side by h
2A/h = bh/h
2A /h = b
Answer:
a-ii
b-iii
c-v
d-i
e-vi
please mark as brainliest
X would equal -3. 5x-3 would equal -15, and 2 negatives would equal a positive. So, -15+3 would equal -12.
