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nevsk [136]
2 years ago
10

Find the midpoint of a and b when a has coordinates (-5,3) and b has coordinates (3,-1)

Mathematics
1 answer:
BlackZzzverrR [31]2 years ago
3 0

Answer:

The midpoint is (2 , 1)

Step-by-step explanation:

To find the midpoint, we have to add the corresponding coordinates

[(-5 , 3) + (3 , -1)] / 2

we separate into the corresponding

(-5 + 3) / 2 =

-2 / 2 = -1

(3 - 1) / 2 =

2 / 2 = 1

The midpoint is (2 , 1)

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What is the perimeter of ABC with vertices at A (-11,4) B(-7,8) and C (-4,4)
Alborosie

Answer:

Step-by-step explanation:

Using the distance formula,

AB=\sqrt{(-11-(-7))^{2}+(4-8)^{2}}=\sqrt{16+16}=4\sqrt{2}\\AC=\sqrt{(-11-(-4))^{2}+(4-4)^{2}}=7\\BC=\sqrt{(-7-(-5))^{2}+(8-4)^{2}}=\sqrt{4+16}=2\sqrt{5}\\\\

So the perimeter is 4\sqrt{2}+7+2\sqrt{5}

3 0
2 years ago
A polygon is shown what is the measure of U
Elan Coil [88]

Answer:

120

Step-by-step explanation:

That's a guess, but it's the most logical one.

6 0
3 years ago
a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei
Masteriza [31]

Answer:

The weight of a small box  = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box  = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) =  5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) =  3 n

Here,   3 large boxes +  5 small boxes =  of 123 kilograms

⇒ 5  m + 3 n = 123   .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) =  2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) =  12 n

Here,   12 large boxes +  2 small boxes =  249 kilograms

⇒ 2 m+ 12 n = 249   .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5  m + 3 n = 123     x (2)

2 m+ 12 n = 249     x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n =  -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5  m + 3 n = 123

So, 5 m = 123  -3 (18.5)  = 123 - 55.5 =  67.5

⇒  m = 13.5

Hence,  the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg  = 18.5 kg

8 0
3 years ago
Write the expression without radicals, using only positive exponents
Mamont248 [21]

Answer:

\sqrt[3]{a^{2}+b^{2}}=(a^{2}+b^{2})^{\frac{1}{3}}

Step-by-step explanation:

∵∛x = (x)^1/3

∴ \sqrt[3]{a^{2}+b^{2}}=(a^{2}+b^{2})^{\frac{1}{3}}

So you can replace the radicals by fractional exponents

7 0
3 years ago
Read 2 more answers
If you have a bag of marbles, 5 blue, 2 red, 6 purple, and 5 green, what is the probability of selecting a blue marble?
Feliz [49]

Answer:

5/18 or about 0.28

Step-by-step explanation:

5 + 2 + 6 + 5 = 18

5/18 or about 0.28

3 0
3 years ago
Read 2 more answers
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