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3 years ago

Complete the square to find the vertex of this parabola.PLEASE HELP!!

Mathematics

1 answer:

Paladinen [302]3 years ago

4 0

Answer:

(1, 5 )

Step-by-step explanation:

Given

x² - 2x + y - 4 = 0 ( add 4 to both sides )

x² - 2x + y = 4

Complete the square on x² - 2x

add ( half the coefficient of the x term )² to both sides

x² + 2(- 1)x + 1 + y = 4 + 1, that is

(x - 1)² + y = 5

Subtract (x - 1)² from both sides

y = - (x - 1)² + 5

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

y = - (x - 1)² + 5 ← is in vertex form

with vertex = (1, 5 )

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3 years ago

A mean ogre stole 24 of your muffins. That was 3/4 of them! With how many did u start with?

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3 years ago

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Answer:

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3 years ago

PLEASE HELP!!!

Novosadov [1.4K]

$\bf \qquad \qquad \textit{sum of an infinite geometric serie}
\\\\
S_n=\sum\limits_{i=1}^{\infty}\ a_1\cdot r^{i-1}\implies S=\cfrac{a_1}{1-r}\quad 
\begin{cases}
a_1=\textit{first term's value}\\
r=\stackrel{0\ \textless \ |r|\ \textless \ 1}{\textit{common ratio}}
\end{cases}$

$\bf \sum\limits_{n=1}^{\infty}~3\left(\frac{1}{4} \right)^{n-1}~~
\begin{cases}
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3 years ago

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Answer:

See below.

Step-by-step explanation:

So we have:

$\exists x\in\mathbb{N},y\in\mathbb{Z}|x^2=y^2$