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dimulka [17.4K]
3 years ago
13

Complete the square to find the vertex of this parabola.PLEASE HELP!!

Mathematics
1 answer:
Paladinen [302]3 years ago
4 0

Answer:

(1, 5 )

Step-by-step explanation:

Given

x² - 2x + y - 4 = 0 ( add 4 to both sides )

x² - 2x + y = 4

Complete the square on x² - 2x

add ( half the coefficient of the x term )² to both sides

x² + 2(- 1)x + 1 + y = 4 + 1, that is

(x - 1)² + y = 5

Subtract (x - 1)² from both sides

y = - (x - 1)² + 5

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

y = - (x - 1)² + 5 ← is in vertex form

with vertex = (1, 5 )

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Anestetic [448]

Answer:

a. -3 < x ≤ 5

b. -3 ≤ y < 3

c.  (0, 0)

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e. -3 < x ≤ - 1, and 1 ≤ x ≤ 3,

f. (-1, -1), and (3, -3)

Step-by-step explanation:

a. The domain of a function is the set of the possible independent variable values which is -3 < x ≤ 5

b. The range of a function is the set of the possible values of the dependent variable which is -3 ≤ y < 3

c. The y-intercept is the point the graph crosses the y-axis

The y-intercept in the graph is the point (0, 0)

d. f(x) ≥ 0  when x = -3, x = 1, x = 5

f(x) ≥ 0 over the following range; -3 < x ≤ - 1.5, 0 ≤ x ≤ 1.5, 4.5 ≤ x ≤ 5

e. The intervals over which f(x) is decreasing are;

-3 < x ≤ - 1, and 1 ≤ x ≤ 3,

f. The local minimums where f(x) has the minimum values are;

(-1, -1), and (3, -3)

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Explanation:
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