<h3>
Answer: Choice A</h3>
Explanation:
Each table has x = 10 in it. Plug this value into the given equation.
y = -2x+17
y = -2*10+17
y = -20+17
y = -3
The input x = 10 leads to the output y = -3. Table A shows this in the middle-most row. So that's why choice A is the answer. The other tables have x = 10 lead to y values that aren't -3 (eg: choice D has x = 10 lead to y = 12), so we can rule them out.
<span>(a) This is a binomial
experiment since there are only two possible results for each data point: a flight is either on time (p = 80% = 0.8) or late (q = 1 - p = 1 - 0.8 = 0.2).
(b) Using the formula:</span><span>
P(r out of n) = (nCr)(p^r)(q^(n-r)), where n = 10 flights, r = the number of flights that arrive on time:
P(7/10) = (10C7)(0.8)^7 (0.2)^(10 - 7) = 0.2013
Therefore, there is a 0.2013 chance that exactly 7 of 10 flights will arrive on time.
(c) Fewer
than 7 flights are on time means that we must add up the probabilities for P(0/10) up to P(6/10).
Following the same formula (this can be done using a summation on a calculator, or using Excel, to make things faster):
P(0/10) + P(1/10) + ... + P(6/10) = 0.1209
This means that there is a 0.1209 chance that less than 7 flights will be on time.
(d) The probability that at least 7 flights are on time is the exact opposite of part (c), where less than 7 flights are on time. So instead of calculating each formula from scratch, we can simply subtract the answer in part (c) from 1.
1 - 0.1209 = 0.8791.
So there is a 0.8791 chance that at least 7 flights arrive on time.
(e) For this, we must add up P(5/10) + P(6/10) + P(7/10), which gives us
0.0264 + 0.0881 + 0.2013 = 0.3158, so the probability that between 5 to 7 flights arrive on time is 0.3158.
</span>
The general form of an equation is
. Solving for (5+X)(5-X)=7 by multiplying the factors and subtratcting 7 on both sides gives the equation
, so
A = 1
B = 0
C = -18
Greater than. For example if you multiply 2 by 3/5 the answer is 1 1/5 which is greater than 3/5
Answer:
Point estimate of the corresponding population mean = $8,213
Step-by-step explanation:
Given:
Average cost of a wedding reception (x) = $8,213
Total number of sample (n) = 450
Standard deviation = $2185
Find:
Point estimate of the corresponding population mean
Computation:
Average cost of a wedding reception (x) = Point estimate of the corresponding population mean
Point estimate of the corresponding population mean = $8,213
