Answer:
2.75 m/s^2
Explanation:
The airplane's acceleration on the runway was 2.75 m/s^2
We can find the acceleration by using the equation: a = (v-u)/t
where a is acceleration, v is final velocity, u is initial velocity, and t is time.
In this case, v is 71 m/s, u is 0 m/s, and t is 26.1 s Therefore: a = (71-0)/26.1
a = 2.75 m/s^2
Answer:
(A) 12.222 ohm (B) 990 W
Explanation:
We have given the voltage of the heating element V = 110 V
The current in the heating element i = 9 A
(a) According to ohm's law V =iR
So 
(b) The power dissipated in the resistor is given by 
So the power dissipated = 990 W
<u>Answer</u>:
(C) The positive charge of the alpha particles and the negative charge of the electrons are the properties Rutherford used in his experiment
<u>Explanation</u>:
In his scattering experiment, scientist Ernest Rutherford used the property of positively charged alpha particles and negatively charge electrons. He performed this experiment by passing some of the alpha particles through a gold foil. The result was that the some alpha particles scattered while some passed through the gold foil without collision.
He concluded that the alpha particles are centrally positively charged and needed a large amount repelling force. This experiment of Rutherford is also known as Rutherford model of atom. This experiment helped him in doing so many other discoveries.
Usually in the deep sea and underwater caves where there is no light
To solve this problem we apply the concepts related to the Intensity, which is defined as the Power given by the object on unit area. Mathematically this is,
Where,
I = Intensity
P = Power
A = Area
Considering that a whisper is around to 
, then we have that
Intensity level in
Where,
Threshold intensity level
Therefore the corresponding sound intensity level is 14dB
