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RoseWind [281]
3 years ago
8

Jasmine is a cook, and she wants to buy new equipment. She is presented with dishes made of copper, clay, plastic, and glass. Sh

e selects the copper pot because she does most of her cooking on the stove.
Which explains why she most likely chose copper?

1.Copper is shiny and reflects light, which will cook the food.
2.Copper is malleable and can be manipulated to cook food.
3.Copper is ductile and can be stretched to cook the food.
4.Copper is conductive and will absorb heat to cook the food.
Physics
2 answers:
Mademuasel [1]3 years ago
6 0

Answer:

D.) Copper is conductive and will absorb heat to cook the food.

Explanation:

-Dominant- [34]3 years ago
5 0
I would say that the answer is 4.) because if she does most of cooking on the stove, that would allow us to make the assumption that she is using heat and therefore requires and apparatus that conducts heat. Copper is also a metallic that is known to be conductive.
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Two identical bowling balls are rolling on a horizontal floor without slipping. The initial speed of both balls is v = 10 m/s. B
Lapatulllka [165]

Answer:

The difference between frictionless ramp and a regular ramp is that on a frictionless ramp the ball cannot roll it can only slide, but on a regular ramp the ball can roll without slipping.

We will use conversation of energy.

K_A_1 + U_A_1 = K_A_2 + U_A_2\\\frac{1}{2}I\omega^2 + \frac{1}{2}mv^2 + 0 = 0 + mgH_A

Note that initial potential energy is zero because the ball is on the bottom, and the final kinetic energy is zero because the ball reaches its maximum vertical distance and stops.

For the ball B;

K_B_1 + U_B_1 = K_B_2 + U_B_2

\frac{1}{2}I_B\omega^2 + \frac{1}{2}mv^2 + 0 = 0 + mgH_B

The initial velocities of the balls are equal. Their maximum climbing point will be proportional to their final potential energy. Since their initial kinetic energies are equal, their final potential energies must be equal as well.

Hence, both balls climb the same point.

Explanation:

4 0
3 years ago
The instruction booklet for your pressure cooker indicates that its highest setting is 12.3 psi . you know that standard atmosph
zmey [24]
<span>118 C The Clausius-Clapeyron equation is useful in calculating the boiling point of a liquid at various pressures. It is: Tb = 1/(1/T0 - R ln(P/P0)/Hvap) where Tb = Temperature boiling R = Ideal Gas Constant (8.3144598 J/(K*mol) ) P = Pressure of interest Hvap = Heat of vaporization of the liquid T0, P0 = Temperature and pressure at a known point. The temperatures are absolute temperatures. We know that water boils at 100C at 14.7 psi. Yes, it's ugly to be mixing metric and imperial units like that. But since we're only interested in relative pressure differences, it's safe enough. So P0 = 14.7 P = 14.7 + 12.3 = 27 T0 = 100 + 273.15 = 373.15 And for water, the heat of vaporization per mole is 40660 J/mol Let's substitute the known values and calculate. Tb = 1/(1/T0 - R ln(P/P0)/Hvap) Tb = 1/(1/373.15 K - 8.3144598 J/(K*mol) ln(27/14.7)/40660 J/mol) Tb = 1/(0.002679887 1/K - 8.3144598 1/K ln(1.836734694)/40660) Tb = 1/(0.002679887 1/K - 8.3144598 1/K 0.607989372/40660) Tb = 1/(0.002679887 1/K - 5.055103194 1/K /40660) Tb = 1/(0.002679887 1/K - 0.000124326 1/K) Tb = 1/(0.002555561 1/K) Tb = 391.3034763 K Tb = 391.3034763 K - 273.15 Tb = 118.1534763 C Rounding to 3 significant figures gives 118 C</span>
3 0
3 years ago
Is this circuit parallel or inseries ​
muminat

Answer:

parallel circuit, hopefully I wasn't late in sending the answer

4 0
2 years ago
If a car is traveling at a constant speed of 100 kilometers per hour (km/h), how many hours will it take for the car to travel a
Ede4ka [16]

Answer:

i believe it is 5

Explanation:

because if it moves at 100 miles per hour after 5 hours you will have 500 miles

because 5 multiplied by 100 equals 500

6 0
2 years ago
Read 2 more answers
How do I find the velocity of a moving object?
Aliun [14]
If you know the distance and the time I travelled that distance.


You just have to divide the time from the distance to get velocity

V =d
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t
8 0
3 years ago
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