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ser-zykov [4K]
3 years ago
13

Please help ASAP. Please show ur work

Mathematics
1 answer:
Vaselesa [24]3 years ago
6 0
The answer is

2. 2a+12

Show work

2a+7+2a+7+4+4= 4a+22

A+2+a+2+3+3 = 2a+10

(4a+22)-(2a+10) = 2a+12
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6.4 divided by 43.52
astraxan [27]

Answer:

0.14705882352

Step-by-Step:

Just use a calculator and your answer should pop up.

7 0
2 years ago
Trapezoid WXYZ has the following measurements, where the length of WZ is equal to the length of XY. WX = 7 ft, WZ = 6 ft, ZY = 2
steposvetlana [31]

Answer: 16 ft.

The Median of a trapezoid is the average of the bases put together.

7 0
3 years ago
7. A machine produces memory sticks of varying lengths, distributed uniformly between 3mm and 13 mm. Memory sticks longer than 1
Mars2501 [29]

Answer:

The proportion of memory sticks that will be scrapped is 0.3 = 30%.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.  

The probability of finding a value of at lower than x is:

P(X < x) = \frac{x - a}{b - a}

The probability of finding a value between c and d is:

P(c \leq X \leq d) = \frac{d - c}{b - a}

The probability of finding a value above x is:

P(X > x) = \frac{b - x}{b - a}

Distributed uniformly between 3mm and 13 mm.

This means that a = 3, b = 13

Calculate the proportion of memory sticks that will be scrapped:

P(X > 10) = \frac{13 - 10}{13 - 3} = \frac{3}{10} = 0.3

The proportion of memory sticks that will be scrapped is 0.3 = 30%.

6 0
2 years ago
Solve for x: -2x-4&gt;8
satela [25.4K]

x<-6

Hope I helped :)

3 0
3 years ago
Read 2 more answers
Two water balloons were launched into the air at different moments and collided. the water balloons were modeled by the quadrati
DerKrebs [107]

Two water balloons were launched into the air at different moments and collided. the water balloons were modeled by the quadratic functions: y = −7x2 26x 3 and y = −6x2 23x 5, where y represents the height in meters and x represents the time in seconds after the launch. 2.0 seconds is the time, in seconds, that the balloons collided at the highest point

The time in seconds that the balloons collided at the highest point is; B: 2.0 seconds

We are told that the water balloons were modeled by the quadratic functions:

y = -7x² + 26x + 6 and y = -6x² + 25x + 4

where;

y = the height in meters

x = the time in seconds after the launch

The time at which they will collide has to be at the same height.

Thus;

-7x² + 26x + 6 = -6x² + 25x + 4

Rearranging this gives;

x² - x - 2 = 0.

Using an online quadratic equation solver gives us x = 2 or -1. We will take the positive one as x = 2.0 seconds

Learn more about quadratic equations at

brainly.com/question/1214333

#SPJ4

5 0
2 years ago
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