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ser-zykov [4K]
3 years ago
13

Please help ASAP. Please show ur work

Mathematics
1 answer:
Vaselesa [24]3 years ago
6 0
The answer is

2. 2a+12

Show work

2a+7+2a+7+4+4= 4a+22

A+2+a+2+3+3 = 2a+10

(4a+22)-(2a+10) = 2a+12
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Notebooks cost $1.20 each. This weekend they will be on sale for $0.80. What percentage is the sale?
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33% off you are paying 66%
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2 years ago
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Given the speeds of each runner below, determine who runs the fastest. \text{Katie runs 10 feet per second.} Katie runs 10 feet
Mrrafil [7]

Answer:

noah

Step-by-step explanation:

katie = 10 f/s

ron = 466 f/33s

noah = 559 f/60s

katie = 10 f/s

ron = 466/33 = 14.1212...f/s

noah = 559/60 = 9.3166...f/s

noah is the fastest

4 0
3 years ago
47(x)
Ksenya-84 [330]

Answer:

How is the behavior of food coloring in the cool and heated water different? ... The food coloring in cool water remained at the bottom of the container. ... the food coloring was caused by the movement of heat through the water and the formation of convection currents. The warmer water is less dense, so it rises to the surface.

Step-by-step explanation:

3 0
2 years ago
What is the sum of 21 and 5 times a number f is 61
sukhopar [10]

Answer:

Answer is below

Step-by-step explanation:

21 + 5f = 61       Turn the words into an equation

-21        - 21       Subtract 21 from both sides

5f = 40              Divide both sides by 5

f = 8

If this answer is correct, please make me Brainliest!

5 0
3 years ago
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Suppose a tank contains 400 gallons of salt water. If pure water flows into the tank at the rate of 7 gallons per minute and the
Strike441 [17]

Answer:

Step-by-step explanation:

This is a differential equation problem most easily solved with an exponential decay equation of the form

y=Ce^{kt}. We know that the initial amount of salt in the tank is 28 pounds, so

C = 28. Now we just need to find k.

The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is \frac{dy}{dt}. Thus, the change in the concentration of salt is found in

\frac{dy}{dt}= inflow of salt - outflow of salt

Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:

3(\frac{y}{400})

Therefore,

\frac{dy}{dt}=0-3(\frac{y}{400}) or just

\frac{dy}{dt}=-\frac{3y}{400} and in terms of time,

-\frac{3t}{400}

Thus, our equation is

y=28e^{-\frac{3t}{400} and filling in 16 for the number of minutes in t:

y = 24.834 pounds of salt

6 0
2 years ago
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