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r-ruslan [8.4K]
3 years ago
7

The marine life store would like to set up fish tanks that contain equal numbers of angel fish , sword tales , and guppies. what

is the greatest number of tanks that can be set up if the store has 12 angel fish, 24 sword tales and 30 guppies?
Mathematics
1 answer:
Shalnov [3]3 years ago
7 0
How do people......I just don't understand this
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Whats is 1+1+3+7+8+33542
Murljashka [212]

Answer:

33562, You could have used a calculator, or used your head, why

Step-by-step explanation:

7 0
3 years ago
ed ReviewA company makes bars of soap.soapThe is mixed in large vats, then poured intomolds to make 560 bars of soap. Themixture
inysia [295]
Given:
weight of mixture : 1792 ounces
output of mixture : 560 bars of soap

to get the weight per unit, we simply divide by total weight by the total number of output.

1792 oz / 560 bars = 3.2 ounces per bar.
6 0
3 years ago
Please help me with this question.​
Stels [109]

Step-by-step explanation:

Mean of the origibal set = 20

No. of terms = 10

Sum = Mean x No. of terms

= 20 x 10 = 200

The sum of additional numbers to make the new set of observstion is 4 + 8 + 12...... + 40 = 220

New Sum = 200 + 220 = 420

The no of terms stay the same

New Mean = New Sum/ N

= 420/10

= 42

7 0
3 years ago
PLEASE HELP the formula m=12,000+12,000rt/12t gives keri's monthly loan payment where t is the annual interest rate and t is the
tatiyna

Answer:

The answer is below

Step-by-step explanation:

The formula m = (12,000 + 12,000rt)/12t gives Keri's monthly loan payment, where r is the annual interest rate and t is the length of the loan, in years. Keri decides that she can afford, at most, a $275 monthly car payment. Give an example of an interest rate greater than 0% and a loan length that would result in a car payment Keri could afford. Provide support for your answer.

Answer: Let us assume an annual interest rate (r) = 10% = 0.1. The maximum monthly payment (m) Keri can afford is $275. i.e. m ≤ $275. Using the monthly loan payment formula, we can calculate a loan length that would result in a car payment Keri could afford.

m=\frac{12000+12000rt}{12t}\\ but\ m\leq275, \ and \ r=10\%=0.1\\275= \frac{12000+12000(0.1)t}{12t}\\275= \frac{12000}{12t} +\frac{12000(0.1)}{12t}\\275= \frac{1000}{t} + 100\\275-100= \frac{1000}{t} \\175= \frac{1000}{t} \\175t = 1000\\t= \frac{1000}{175}\\ t=5.72\ years

The loan must be at least for 5.72 years for an annual interest rate (r) of 10%

3 0
3 years ago
[(2x)^x (2x)^2x]^1/x<br>how do you simplify this?
Monica [59]
Note that [ (2x)^x ]^(1/x) = 2x, and that [ (2x)^(2x) ]^(1/x) = (2x)^2 = 4x^2

Multiplying these 2 results together, we get (2x)(4x^2) = 8x^3 (answer)
5 0
3 years ago
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