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Slav-nsk [51]
3 years ago
10

The _____ theory proposes that the moon was a passing asteroid pulled into orbit by Earth's gravity.

Physics
2 answers:
dem82 [27]3 years ago
5 0
C). capture theory is the correct answer.
Debora [2.8K]3 years ago
3 0
It's the capture theory.
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A 9.5 kg object undergoes an acceleration of 3.3m/s^2. What is the magnitude of the next external force acting on it
Black_prince [1.1K]

The net external force is 31.4 N

Explanation:

We can solve this problem by applying Newton's second law, which states that the net force acting on an object is equal to the product between its mass and its acceleration:

F=ma

where

F is the net force

m is the mass

a is the acceleration

For the object in this problem, we have:

m = 9.5 kg is the mass

a=3.3 m/s^2 is the acceleration

Solving for F, we find the net force:

F=(9.5)(3.3)=31.4 N

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

5 0
3 years ago
Which type of bond and how many bonds would occur as carbon dioxide.. (CO2) is formed from carbon in Group IVA and oxygen in Gro
Ahat [919]

Answer:

four covalent bonds is the answer

3 0
3 years ago
An object that is dropped from a height H falls with a constant acceleration of g. The final
GuDViN [60]

The height need to change by 4 to double the final velocity.

<h3>Final velocity of the object</h3>

The final velocity of an object during a free fall is related to maximum height of fall as given the equation below.

v = √2gh

v² = 2gh

v²/h = 2g

v₁²/h₁ = v₂²/h₂

when v₂ = 2v₁, change in height is calculated as;

h₂ = h₁v₂²/v₁²

h₂ = (h₁ (2v₁)²) / (v₁)²

h₂ = 4h₁v₁² / v₁²

h₂ = 4h₁

Thus, the height need to change by 4 to double the final velocity.

Learn more about final velocity here: brainly.com/question/25905661

#SPJ1

4 0
1 year ago
While at a party, you pull up a sound intensity level app on your phone (everyone does stuff like that, right?), and it reads 83
allochka39001 [22]

To solve this problem it is necessary to apply the concepts related to Sound Intensity. The unit most used in the logarithmic scale is the decibel and mathematically this is expressed as

\beta_{dB} = 10log_{10}\frac{I}{I_0}

Where,

\beta_{dB}= Sound intensity level in decibels

I = Acoustic intensity on the linear scale

I_0 = Hearing threshold

According to the values, the total intensity is 32 times the linear intensity and the value in decibels is 83dB

So:

10log_{10}(\frac{32I}{I_0}) = 83

10log(\frac{I}{I_0})+10log(32) = 83

10log(\frac{I}{I_0})= 83-10log(32)

10log(\frac{I}{I_0})= 67.948dB

Therefore the sound intensity due to one person is 67.948dB

8 0
3 years ago
a sound wave is an example of a a. transverse wave. b. longitudinal wave. c. standing wave. d. surface wave
Leona [35]

Answer:  Longitudinal wave

Explanation:

Longitudinal wave are the oscillations that are parallel to the direction of energy transfer that means the vibrations are in line with the direction where the energy is travelling.

A key feature of sound wave is that they cause sound particles to vibrate. The region where the particles are close together are called compressions and regions where particles are further apart they are called rarefactions.  

The other options explanation:

-Transverse waves are where the oscillations are perpendicular to the energy of transfer.

-A standing wave is where the waves are travelling back and forth where there are some fixed points in the system whilst other vibrate with highest amplitude  

-Surface waves have both the characteristics of longitudinal and transverse waves



8 0
3 years ago
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