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Ket [755]
3 years ago
11

A 2.00-kg rock has a horizontal velocity of magnitude 12.0 m>s when it is at point P in Fig. E10.35. (a) At this instant, wha

t are the magnitude and direction of its angular momentum relative to point.(b) If the only force acting on the rock is its weight, what is the rate of change (magnitude and direction) of its angular momentum at this instant?
Physics
1 answer:
zaharov [31]3 years ago
7 0

Answer:

(A) L = 115.3kgm²/s

(B) dL/dt = 94.1kgm²/s²

Explanation:

The magnitude of the angular momentum of the rock is given by the foemula

L = mvrSinθ

We have been given θ = 36.9°, m = 2.0kg, v = 12.0m/s and r = 8.0m.

Therefore L = 2.00 × 12 × 8.0 × Sin 36.9° =

115.3 kgm²/s

(B) The magnitude of the rate of angular change in momentum is given by

dL /dt = d(mvrSinθ)/dt = mgrSinθ = 2.00 × 9.8 × 8.0× Sin36.9 = 94.1kgm²/s²

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A uniform, spherical, 1900.0 kg shell has a radius of 5.00 m. Find the gravitational force this shell exerts on a 1.80 kg point
Mandarinka [93]

Answer:

F=9.09\times 10^{-9} N

Explanation:

We are given that

Mass of spherical shell,m_1=1900 kg

Mass=m_2=1.80 kg

Radius of shell=r=5 m

Distance between two masses=r=5.01 m

Because distance measure from center .

Gravitational force

F=G\frac{m_1m_2}{r^2}

G=6.67\times 10^{-11} Nm^2/kg^2

Using the formula

F=6.67\times 10^{-11}\times \frac{1900\times 1.80}{(5.01)^2}

F=9.09\times 10^{-9} N

Hence,the gravitational force =F=9.09\times 10^{-9} N

6 0
3 years ago
Waves diffract the most when their wavelength is
djverab [1.8K]
<h2>Answer: about the same size of the gap  or slit</h2>

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Note that the principal condition for the occurrence of this phenomena is that the obstacle must be comparable in size (similar size) to the size of the wavelength.

In other words, when the gap (or slit) size is larger than the wavelength, the wave passes through the gap and does not spread out much on the other side, but when the gap size is equal to the wavelength, maximum diffraction occurs.

Therefore:

<h2>Waves diffract the most when their wavelength is <u>about the same size of the gap </u></h2>

<u />

5 0
3 years ago
How many atoms of hydrogen in the product side of the balanced equation
Anettt [7]

The same number there were on the reactant side, before the reaction.

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3 years ago
An electric pump rated at 1000W, takes 16 seconds to pump 100 kg of water out to a tank at a height of 10 m. what is the efficie
TEA [102]

Answer:

\boxed{\sf Efficiency \ of \ the \ motor = 62.5 \ \%}

Given:

Input Power (\sf P_i)= 1000 W

Mass (m) = 100 kg

Height (h) = 10 m

Time (t) = 16 s

To Find:

Efficiency of the motor

Explanation:

\boxed{ \bold{Output  \: power  \: (P_o)= \frac{mgh}{t}}}

\sf \implies P_o =  \frac{100 \times 10 \times 10}{16}

\sf \implies P_o =  \frac{10000}{16}

\sf \implies P_o =  \frac{ \cancel{16} \times 625}{ \cancel{16}}

\sf \implies P_o = 625 \: W

\boxed{ \bold{Efficiency = \frac{Output \ Power \ (P_o)}{Input \ Power \ (P_i) } \times 100}}

\sf  \implies Efficiency  =  \frac{625}{10 \cancel{00}}  \times  \cancel{100}

\sf  \implies Efficiency  =  \frac{625}{10}

\sf  \implies Efficiency  = 62.5  \: \%

\therefore

Efficiency of the motor = 62.5 %

5 0
3 years ago
Please help anyone i will mark brainliest
Andrei [34K]
Fg = G m₁ m₂ / r²

Fg = (6.67×10−¹¹) ( 70) ( 5.972×10²⁴) / (6.3781×10⁶)²

Fg = 685.43 N
4 0
3 years ago
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