A 2.00-kg rock has a horizontal velocity of magnitude 12.0 m>s when it is at point P in Fig. E10.35. (a) At this instant, wha
1 answer:
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Answer:
No, the acceleration is not always zero.
Explanation:
It does not mean that the acceleration of the particle is zero.
The velocity of wave is different from the velocity of particle.
The acceleration of wave is different from the acceleration of particle.
the acceleration of the particle is given by
where, w is the angular frequency and y is the displacement from the mean position.
So, the acceleration is zero at mean position only and it varies as the position changes.
Answer:
A=1
B=-2
Explanation:
Part A and B of the question wasn't given, however, I attached the relevant parts to solve this question as follows.
From part B as attached, it shows that the right option is C which is
2A+3B=-4
Substituting B with 3A-5 then we form the second equation as shown
2A+3(3A-5)=-4
By simplifying the above equation, we obtain
2A+9A-15=-4
Re-arranging, then
11A=-4+15
Finally
11A=11
A=1
To obtain B, we already know that 3A-5 so substituting the value of A into the above then we obtain
B=3(1)-5=-2
Therefore, required values are 1 and -2
Answer:103 pounds
Explanation:
Given
width of window
height of window
standard atmospheric pressure
Also
Thus Net Force on the window will be the algebraic sum of Force due to outside and inside Pressure .