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kupik [55]
3 years ago
13

A solid uniform cylinder of mass 4.1 kg and radius 0.057 m rolls without slipping at a speed of 0.79 m/s. What is the cylinder’s

total kinetic energy?
Physics
1 answer:
Amiraneli [1.4K]3 years ago
8 0

Answer:

The cylinder’s total kinetic energy is 1.918 J.

Explanation:

Given that,

Mass = 4.1 kg

Radius = 0.057 m

Speed = 0.79 m/s

We need to calculate the linear kinetic energy

Using formula of linear kinetic energy

K.E_{l}=\dfrac{1}{2}mv^2

K.E_{l}=\dfrac{1}{2}\times4.1\times(0.79)^2

K.E_{l}=1.279\ J

We need to calculate the rotational kinetic energy

K.E_{r}=\dfrac{1}{2}\times I\omega^2

K.E_{r}=\dfrac{1}{2}\times\dfrac{1}{2}\times mr^2\times(\dfrac{v}{r})^2

K.E_{r}=\dfrac{1}{4}\times m\times v^2

K.E_{r}=\dfrac{1}{4}\times4.1\times(0.79)^2

K.E_{r}=0.639\ J

The total kinetic energy is given by

K.E=K.E_{l}+K.E_{r}

K.E=1.279+0.639

K.E=1.918\ J

Hence, The cylinder’s total kinetic energy is 1.918 J.

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