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WINSTONCH [101]
3 years ago
11

What is the Ultraviolet Catastrophe?​

Physics
1 answer:
Sholpan [36]3 years ago
7 0

The ultraviolet catastrophe was the prediction of late 19th century/early 20th century classical physics that an ideal black body (also blackbody) at thermal equilibrium will emit radiation in all frequency ranges, emitting more energy as the frequency increases.

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Work occurs when
defon
I believe the answer is the second option.
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4 years ago
a block of wood is floating in water. the weight of the part of the block above water is one-third of the total weight of the bl
andrey2020 [161]
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The weight of the water displaced is the same as the total weight of the wood block. The fact that 1/3 of the block is above the water level does not matter if you just weigh the total block of wood , then the weight of the total block of wood = the weight of the water displaced by the block of wood. If you want to find density of the block of wood that is a different question - then you need the volume of the block of wood and the information about one- third of the total weight . I hope this helped</span>
3 0
4 years ago
Read 2 more answers
Với vo= 72km/h thì hãm phanh chuyển động chậm dần đều, sau 10s đạt v1= 54km/h.
Crazy boy [7]

Answer:

B

Explanation:

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4 0
3 years ago
1. What was the common belief (theory) about motion before the 1600's?
Rina8888 [55]
People then didn't really think about gravity, they simply accept the fact that it exists, without realising. View this from another angle. When a teacher explains something in the classroom, most of the time we simply accept it, without asking why. That right there, is acceptance. We simply accept it. Everyone would know that if they let go of something, it would drop. However, only Isaac Newton stopped to question why. Hope this helps :)
7 0
3 years ago
Water flowing through a pipe suddenly comes to a section of pipe where the pipe diameter decreases to 86% of its previous value.
lord [1]
In all the sections of the pipe, volumetric flow rate is the same. Therefore,
Q1 = Q2

Q = VA, V = velocity, A = Cross-sectional area.

Then,
V1A1 = V2A2

But,
A = πD^2/4
Then,
V1·πD1^2/4 = V2·πD2^2/4
V1·D1^2 = V2·D2^2

But
D2/D1 = 86% = 0.86, or D1/D2 = 1/0.86
Therefore,
V2 = (V1D1^2)/D2^2 = V1·(D1/D2)^2 = 66*(1/0.86)^2 = 89.24 m/s

The speed in the smaller section is 89.24 m/s.
4 0
3 years ago
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