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boyakko [2]
3 years ago
12

To find original research in animal disease prevention, it would be best to consult a/an

Physics
1 answer:
yarga [219]3 years ago
6 0
The correct answer that would best complete the given statement above would be PERIODICAL OR TRADE JOURNAL. To find <span>original research in animal disease prevention, it would be best to consult a periodical or trade journal. A trade journal is a journal that contains news of interest about a specific trade. </span>
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A brave child decides to grab onto an already spinning merry‑go‑round. The child is initially at rest and has a mass of 34.5 kg.
ozzi

Answer:

I_1 = 32.5 kg m^2

Explanation:

Here as we know that total angular momentum is always conserved for child + round system

so here by angular momentum conservation we have

I_1 \omega_1 = (I_1 + I_2)\omega_2

here we have

I_2 = mR^2 (inertia of boy)

I_2 = (34.5)(1.45^2)

I_2 = 72.5 kg m^2

now we have

I_1(2\pi 55) = (I_1 + 72.5)(2 \pi 17)

I_1 = (I_1 + 72.5)(0.31)

I_1(1 - 0.31) = 22.4

I_1 = 32.5 kg m^2

3 0
3 years ago
Why centre of gravity of ring is out of its body
earnstyle [38]
There's no reason why the center of gravity must be in a place where
there is a any mass. 

The center of gravity is simply a LOCATION ... the place where the 
amount of mass in any direction from it is the same amount. 

For that matter, whenever you know the location of the center of gravity
for ANY object, you can always go in there and scoop our a tiny spherical
hole at that place.  Then the center of gravity won't move, but it will be in an
empty space, 'outside the body' of the object.

Here are a few more points to ponder:

-- The center of gravity of a basketball, beach ball, tennis ball, or any other
inflated ball is the center of the ball, where there is no part of the skin.

-- The center of gravity of a party balloon is somewhere inside the balloon,
where there is no rubber.  If the balloon is spherical, then its center of gravity
is the center of the sphere.

-- The center of gravity of a square is the center of the square, not on any
of its sides.

-- The center of gravity of a triangle is the centroid of the triangle, not on any
of its sides.

8 0
3 years ago
A sound wave has a frequency of 425 Hz. What is the period of this wave?
Serhud [2]
Period is 1/frequency
1/425 = 2.353ms
8 0
3 years ago
A reactor operating at 1 MW is scrammed by instantaneous insertion of $5.00 of negative reactivity. Approximately how long does
Novosadov [1.4K]

Answer:

time is 3333.33 min or 55.55 hr

Explanation:

given data

reactor operating = 1 MW

negative reactivity =  $5

power = 1 miliwatt

to find out

how long does it take

solution

we know here power coefficient that is

power coefficient = \frac{10^{6} }{10^{6} }

power coefficient = 1

so time required to reach power is

power =  reactivity × time / power coefficient + reactor operating

1 × 10^{-3} = -5 t / 1  +  1 × 10^{6}

5t =  10^{6} - 10^{-3}

t = 199999.99 sec

so time is 3333.33 min or 55.55 hr

4 0
4 years ago
When the distance between two masses is doubled, the gravitational attraction between
mrs_skeptik [129]

The new gravitational attraction will be 1/4 as much

Explanation:

The magnitude of the gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

In this problem, the original force between the two objects is F, when they are separated by a distance r.

Later, the distance between the two objects is doubled, so the new distance is

r'=2r

Therefore, the new force will be

F'=G\frac{m_1 m_2}{(2r)^2}=\frac{1}{4}(\frac{Gm_1 m_2}{r^2})=\frac{F}{4}

Therefore, the new force will be one-fourth as much.

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

5 0
3 years ago
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