We have that the speed of a body covering a distance of 320 km in 4h is mathematically given as
V=22.22m/s is
<h3 /><h3>From the question we are told
calculate the speed of a body covering a distance of 320 km in 4h
Generally the equation for the Speed is mathematically given as
V=22.22m/s
Hence
The speed of a body covering a distance of 320 km in 4h is
V=22.22m/s
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Answer:
The kinetic energy of the ejected electrons increases.
Explanation:
As we know that electrons are only ejected from a metal surface if the frequency of the incident light increases the work function of the metal. If the frequency of the incident light is less than the work function of the metal no matter how intense the beam the electrons will not be ejected from the surface.
Using conservation of energy principle we have
If we increase the intensity of incident light the term on the LHS of the above equation increases this increase appears in the kinetic energy term in RHS of the equation since remains constant.
Explanation:
The force of the roller-coaster track on the cart at the bottom is given by :
, m is mass of roller coaster
Case 1.
R = 60 m v = 16 m/s
Case 2.
R = 15 m v = 8 m/s
Case 3.
R = 30 m v = 4 m/s
Case 4.
R = 45 m v = 4 m/s
Case 5.
R = 30 m v = 16 m/s
Case 6.
R = 15 m v =12 m/s
Ranking from largest to smallest is given by :
F>E>A=B>C>D