<u>Answer</u>
5) b-c
6) a-b and
e-f
7) f-g
9) a-b = 0 m/s
c-d = 0.6667 m/s
e-f = 0 m/s
f-g = -3 m/s
10) b-c ⇒ The cart is acceleration.
e-f ⇒ The cart is moving backwards with a constant velocity.
<u>Explanation</u>
Answer
5) b-c
In the section b-c the cart is accelerating because the slope of the graph is changing. The gradient that represent velocity is increasing.
6) a-b and e-f
At this sections the distance is not changing at all. This can only mean that the cart is not moving. It is at rest.
7) f-g
At this section the slope is negative meaning the cart is moving back to where it came from.
9) a-b = 0 m/s
At a-b the cart is not moving. So the velocity is zero.
<u> c-d = 0.66667 m/s</u>
Velocity = distance / time
=(50-40)/(40-25)
= 10/15
= 0.6667 m/s
<u> e-f = 0 m/s</u>
At e-f the cart is not moving. So the velocity is zero.
<u> f-g = -3 m/s</u>
Velocity = distance / time
= (60-30)/(65-75)
= 30/-10
= - 3 m/s
10) b-c ⇒ The cart is acceleration.
e-f ⇒ The cart is moving backwards with a constant velocity.
Answer:
A. There is a localization of positive charge near the door handle.
Explanation:
- When on a cold morning a person wearing cotton/ polyester cloth walking on the carpet moves toward his car then due to friction between the feet and the carpet there are transfer of electrons from the carpet to our feet, and since our body is a good conductor of electricity the charges spread throughout on the surface of or body.
- When the person brings his hands close to the neutral conducting door of the car it gets induced with equal intensity of opposite charge to our hands thus having a concentration of positive charges near to the hand on the car's door is developed as a result of polarization within the conductor.
Answer:
<em>The actual dimensions of the classroom are 50 cm x 70 cm</em>
Explanation:
<u>Scaling
</u>
When we need to represent real-world dimensions into small spaces, we use scaling. Distance scaling tells us what is the equivalence between the real units and the scaled units. In this case, we are told that 10 cm is equivalent to 1 meter. As 1 meter is 100 cm, it means that the scale is 100/10=10. Thus, each centimeter in the paper is equivalent to 10 cm in the real distance.
The classroom is 5 cm x 7 centimeters. Scaling back to the real values, the classroom has measures of 50 cm x 70 cm.
<span>Plug in 288 for h, move it over to the right side and do the quadratic formula to solve for t. You will get 2 times, in between and including those times will give you the period it is at least 288 ft off the ground.
</span>You can simplify this and not need to use the quadratic.
<span>288=−16<span>t^2</span>+144t
</span><span>Divide through by 16 getting
18=-t^2 + 9t
</span><span><span>t^2</span>−9t+18=0</span><span> Is what you would get after rearranging the equation Now you have something you can easily factor</span><span>
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