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aivan3 [116]
3 years ago
11

The ratio of the muffins Baker A baked to the number of muffins Baker B baked was 8 : 5. The ratio of the number of muffins Bake

r B baked to the number of muffins BAker C baked was 4 : 3. If Baker C baked 150 muffins, how many more muffins did Baker A bake than Baker C?
Mathematics
1 answer:
Ksju [112]3 years ago
8 0

Answer:

170 muffins

Step-by-step explanation:

We start from the ratio between baker B and C

The ratio of cakes baked by both is 4:3.

We know baker C baker 150 muffins:

This mathematically means:

B:C = 4:3 = B:150

This means 4/3 = B/150

B = (4 * 150)/3 = 200

Baker B baked 200 cakes

We now move back to the first statement

The ratio between baker A and B is 8:5

Mathematically, this means:

A:B = 8:5 = A:200

8/5 = A/200

A = (8 * 200)/5 = 320

The number of cakes baker A baker pass baker C would be 320 - 150 = 170 muffins

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borishaifa [10]

Answer:

432 in.^2

Step-by-step explanation:

The side of the suitcase is a rectangle. One length is 24 inches. The diagonal of the rectangle is 30 inches long. The diagonal is a hypotenuse of a right triangle. The length is a leg. We need to find the other leg.

We use the Pythagorean theorem,

a^2 + b^2 = c^2

(24 in.)^2 + b^2 = (30 in.)^2

576 in.^2 + b^2 = 900 in.^2

b^2 = 324 in.^2

b = sqrt(324 in^2)

b = 18 in

area of rectangle = length * width

A = 24 in. * 18 in.

A = 432 in.^2

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3 years ago
What is (2+y)³ written out?
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{ \left( 2+y \right)  }^{ 3 }\\ \\ =\left( 2+y \right) \left( 2+y \right) \left( 2+y \right) \\ \\ =\left( 2+y \right) \left( 4+4y+{ y }^{ 2 } \right)

\\ \\ =2\left( 4+4y+{ y }^{ 2 } \right) +y\left( 4+4y+{ y }^{ 2 } \right) \\ \\ =8+8y+2{ y }^{ 2 }+4y+4{ y }^{ 2 }+{ y }^{ 3 }\\ \\ ={ y }^{ 3 }+6{ y }^{ 2 }+12y+8
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3 years ago
A grid model with 50 squares. 25 squares are shaded.
alekssr [168]

Answer:

Do you still need this answered

Step-by-step explanation:

8 0
3 years ago
Find the area of the shaded region.
luda_lava [24]

Answer:

The area of the shaded region is 11.6\ cm^{2}

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of the sector of circle of angle 68.9 degrees minus the area of the isosceles triangle

step 1

Find the area of sector of the circle

The area of circle is equal to

A=\pi r^{2}

assume

\pi =3.14

r=9.28\ cm

substitute

A=(3.14)(9.28)^{2}

A=270.41\ cm^{2}

Remember that the area of a circle subtends a central angle of 360 degrees

so

using proportion Find out the area of a sector with a central angle of 68.90 degrees

Let

x -----> the area of a sector

270.41/360=x/68.90\\\\x=68.90*270.41/360\\\\x=51.75\ cm^{2}

step 2

Find the area of the isosceles triangle

Applying the law of sines

The area is equal to

A=(1/2)r^{2}sin(68.90)

we have

r=9.28\ cm

substitute

A=(1/2)(9.28)^{2}sin(68.90)=40.17\ cm^{2}

step 3

Find the area of the shaded region

51.75-40.17=11.58\ cm^{2}

Round to the nearest tenth

11.58=11.6\ cm^{2}

3 0
3 years ago
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