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aivan3 [116]
3 years ago
11

The ratio of the muffins Baker A baked to the number of muffins Baker B baked was 8 : 5. The ratio of the number of muffins Bake

r B baked to the number of muffins BAker C baked was 4 : 3. If Baker C baked 150 muffins, how many more muffins did Baker A bake than Baker C?
Mathematics
1 answer:
Ksju [112]3 years ago
8 0

Answer:

170 muffins

Step-by-step explanation:

We start from the ratio between baker B and C

The ratio of cakes baked by both is 4:3.

We know baker C baker 150 muffins:

This mathematically means:

B:C = 4:3 = B:150

This means 4/3 = B/150

B = (4 * 150)/3 = 200

Baker B baked 200 cakes

We now move back to the first statement

The ratio between baker A and B is 8:5

Mathematically, this means:

A:B = 8:5 = A:200

8/5 = A/200

A = (8 * 200)/5 = 320

The number of cakes baker A baker pass baker C would be 320 - 150 = 170 muffins

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The mean one-way commute to work in Chowchilla is 7 minutes. The standard deviation is 2.4 minutes, and the population is normal
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Answer:

The answer is below

Step-by-step explanation:

Given that:

The mean (μ) one-way commute to work in Chowchilla is 7 minutes. The standard deviation (σ) is 2.4 minutes.

The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z=\frac{x-\mu}{\sigma}

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z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

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b) For x = 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

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z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67

From normal distribution table, P(2 < x < 11) = P(-2.08 < z < 1.67 ) = P(z < 1.67) - P(z < -2.08) = 0.9525 - 0.0188 = 0.9337  

c) For x = 11:

z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67

From normal distribution table,  P(x < 11) = P(z < 1.67) = 0.9525

d) For x = 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

For x = 5:

z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83

From normal distribution table, P(2 < x < 5) = P(-2.08 < z < -0.83 ) = P(z < -0.83) - P(z < -2.08) =  0.2033- 0.0188 = 0.1845  

e) For x = 5:

z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83

From normal distribution table,  P(x < 5) = P(z < -0.83) = 0.2033

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4 years ago
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