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3 years ago

Q1: Erosion and weathering are often confused. How is erosion different from weathering? Give an example of each.

Chemistry

1 answer:

stepan [7]3 years ago

6 0

Explanation:

Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soils whereas erosion is the movement of weathered materials from one area to the other.

Erosion moves weathered materials and it causes them to change position. For example loose chips of rocks broken down as the rock weakens through alternate wetting and drying in tropical regions will remain in-situ until the agents of erosion comes to carry them away. The breaking is weathering and the carrying is erosion.

Learn more:

Wind erosion brainly.com/question/2115729

Examples of mechanical weathering:

Frost action
Pressure release

Examples of chemical weathering:

Oxidation
Carbonation

There are two types of weathering:

In mechanical weathering, a rock disintegrates into smaller chunks by the action of wind, water and glacier. For example in temperate and polar regions, water within rocks freezes. When water freezes it expands and causes tension within the rock. When temperature drops, water melts and the tension is relieved. This process causes a rock to crack. The crack will eventually become wider with time.
In chemical weathering, a rock decomposes by the action of chemicals formed in the rock. In karst regions where limestone forms, combination of rain water and carbon dioxide forms weak carbonic acid that reacts with calcite in limestone.

Learn more:

Erosion brainly.com/question/2473244

#learnwithBrainly

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A 1.00 kg sample of Sb2S3 (s) and a 10.0 g sample of H2 (g) are allowed to react in a 25.0 L container at 713 K. At equilibrium,

Scorpion4ik [409]

Answer: The value of $K_c$ is coming out to be 0.412

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For $Sb_2S_3$

Given mass of $Sb_2S_3$ = 1.00 kg = 1000 g (Conversion factor: 1 kg = 1000 g)

Molar mass of $Sb_2S_3$ = 339.7 g/mol

Putting values in equation 1, we get:

$\text{Moles of }Sb_2S_3=\frac{1000g}{339.7g/mol}=2.944mol$

For hydrogen gas:

Given mass of hydrogen gas = 10.0 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrogen gas}=\frac{10.0g}{2g/mol}=5mol$

For hydrogen sulfide:

Given mass of hydrogen sulfide = 72.6 g

Molar mass of hydrogen sulfide = 34 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrogen sulfide}=\frac{72.6g}{34g/mol}=2.135mol$

The chemical equation for the reaction of antimony sulfide and hydrogen gas follows:

$Sb_2S_3(s)+3H_2(g)\rightarrow 2Sb(s)+3H_2S(g)$

Initial: 2.944 5

At eqllm: 2.944-x 5-3x 2x 3x

We are given:

Equilibrium moles of hydrogen sulfide = 2.135 moles

Calculating for 'x', we get:

$\Rightarrow 3x=2.135\\\\\Rightarrow x=\frac{2.135}{3}=0.712$

Equilibrium moles of hydrogen gas = (5 - 3x) = (5 - 3(0.712)) = 2.868 moles

Volume of the container = 25.0 L

Molarity of a solution is calculated by using the formula:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}$

The expression of $K_c$ for above equation, we get:

$K_c=\frac{[H_2S]^3}{[H_2]^3}$

The concentration of solids and liquids are not taken in the expression of equilibrium constant.

$K_c=\frac{(\frac{2.135}{25})^3}{(\frac{2.868}{25})^3}\\\\K_c=0.412$

Hence, the value of $K_c$ is coming out to be 0.412

3 0

3 years ago

Mrs. Nogaki tested four black markers in rubbing alcohol and in water. Each filter paper had four evenly spaced dots. She found

ExtremeBDS [4]

Answer:

Lost pigment of marker when dipped in alcohol

Explanation:

dependent viable = output

so it's the output of what happens after the input.

she put the marker in the water which is the independent variable, that's the input
the output or the result of that decision is having lost pigment in the marker

8 0

3 years ago

What does this mean 1.000 atm=101.3kpa

jenyasd209 [6]

Answer:

The standard value of atmospheric pressure at sea level

Explanation:

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3 years ago

If you burn 10 kilograms of wood in a fire (combustion) what is the weight of the products after the fire has finished burning t

sleet_krkn [62]

The answer is: the weight of products is is equal the weight of the wood plus the weight of oxygen that was used to burn that wood, so weigh of the product is greater than 10 kilograms.

Conservation of mass (mass is never lost or gained in chemical reactions), during chemical reaction no particles are created or destroyed, the atoms are rearranged from the reactants to the products.

In this example wood (mostly carbon) and oxygen are reactants and carbon dioxide (mostly) is product of reaction.

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3 years ago

Can someone please explain core and valence electrons in periods for me please

Lena [83]

Answer:

The electrons of an atom are typically divided into two categories: valence and core electrons. Valence electrons occupy the outermost shell or highest energy level of an atom while core electrons are those occupying the innermost shell or lowest energy levels

Explanation:

i hope u get it :))

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3 years ago