Answer : The heat released by the combustion of 1.121 mol of hexane (kJ) is,
Explanation :
The given balanced reaction is,
Given:
Moles of hexane = 0.121 mol
= -8326 kJ/mol
The negative sign indicate that the reaction exothermic or amount of heat released.
As, 1 mole of hexane released heat = 8326 kJ
So, 0.121 mole of hexane released heat = 8326 × 0.121 = 1007.446 ≈
Therefore, the heat released by the combustion of 1.121 mol of hexane is .
The correct answer among the choice listed is the third option. The reaction between silver nitrate and potassium hydroxide will yield a precipitate which is the silver hydroxide product. This is because this substance is not very soluble in aqueous solution.
Answer:
Volume of water
Initial temperature of the solution
Final temperature of the solution
Mass of NH₄Cl
Explanation:
There are two heat transfers involved in this experiment.
Heat of solution of NH₄Cl + heat lost by water = 0
q₁ + q₂ = 0
nΔH + mCΔT = 0
nΔH = -mCΔT
ΔH = -mCΔT/n
So, you must measure
- the volume of water (you will probably use its density to calculate its mass)
- the initial and final temperatures of the solution (to calculate ΔT)
- the mass of NH₄Cl (to calculate the number of moles)
You will probably assume that the specific heat capacity of the solution is the same as that of water, so you won't be measuring it.
Answer:
Order zero
Explanation:
Let's consider the decomposition of ammonia to nitrogen and hydrogen on a tungsten filament at 800°C.
2 NH₃(g) → N₂(g) + 3 H₂(g)
The generic rate law is:
rate = k × [NH₃]ⁿ
where,
rate: reaction rate
k: rate constant
n: reaction order
When n = 0, we get:
rate = k × [NH₃]⁰ = k
As we can see, when the reaction order with respect to ammonia is zero, the reaction rate is independent of the concentration of ammonia.