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netineya [11]
3 years ago
8

Watch the animation depicting Rutherford’s experiment and choose which of the following conclusions are correct.a. The atom cont

ains a positively charged nucleus. b. Positive charge is condensed in one location within the atom. c. The majority of the space inside the atom is empty space. d. A positive charge is spread equally over the atom. e. The mass of an atom is concentrated at the nucleus. f. The atom is a very compact entity without any em
Chemistry
1 answer:
Lilit [14]3 years ago
4 0

Answer:

a, b, c, d

Explanation:

Rutherford’ atomic model is based on the gold foil experiment. In this experiment, beam of alpha rays was bombarded on thin gold foil. He observed that:

Most of the alpha particles passed through thin foil without any deflection.

Few alpha particles deflected by an angle of 90o.

Based on observation, Rutherford concluded that majority of the space inside the atom is empty.

He explained defection of few alpha particles by assuming that most of the mass is concentrated at the nucleus and positively charged.  

Therefore, among given, the correct statements are:

The atom contains a positively charged nucleus.

Positive charge is condensed in one location within the atom.

The majority of the space inside the atom is empty space

The mass of an atom is concentrated at the nucleus

Therefore, the correct options are:

a, b, c, d

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3 years ago
Rxn
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Answer: The enthalpy of formation of SO_3 is  -396 kJ/mol

Explanation:

Calculating the enthalpy of formation of SO_3

The chemical equation for the combustion of propane follows:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(2\times \Delta H^o_f_{(SO_3(g))})]-[(2\times \Delta H^o_f_{(SO_2(g))})+(1\times \Delta H^o_f_{(O_2(g))})]

We are given:

\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(SO_2(g))}=-297kJ/mol\\\Delta H^o_{rxn}=-198kJ

Putting values in above equation, we get:

-198=[(2\times \Delta H^o_f_{(SO_3(g))})]-[(2\times \Delta -297)+(1\times (0))]\\\\\Delta H^o_f_{(SO_3(g))}=-396kJ/mol

The enthalpy of formation of SO_3 is -396 kJ/mol

4 0
3 years ago
In the following question, select the odd word from the given alternatives.
mote1985 [20]

Answer:

c

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What is properties of matter​
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Explanation:

color (intensive)

density (intensive)

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7 0
3 years ago
Read 2 more answers
Which formula is an empirical formula?
poizon [28]
<h2>Hello!</h2>

The answer is:

The empirical formula is the option B. NH_{3}

<h2>Why?</h2>

The empirical formula of a compound is the simplest formula that can be written. On the opposite, the molecular formula involves a variant of the same compound, but it can be also simplified to an empirical formula.

MolecularFormula=n(EmpiricalFormula)

We are looking for a formula that cannot be simplified by dividing the number of molecules/atoms that conforms the compound.

Let's discard option by option in order to find which formula is an empirical formula (cannot be simplified)

A. N_{2}O_{4}

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

N_{2}O_{4}=2(NO_{2})

B. NH_{3}

It's an empirical formula since it cannot be obtained by the multiplication of a whole number and the simplest formula. It's the simplest formula that we can find of the compound.

C. C_{3}H_{6}

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

C_{3}H_{6}=3(CH_{2})

D. P_{4}O_{10}

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

P_{4}O_{10}=2(P_{2}O_{5})

Hence, the empirical formula is the option B. NH_{3}

Have a nice day!

6 0
3 years ago
Read 2 more answers
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