The figure before translation is the pre-image, after the image has been translated, it is just the "image."
Answer:
-1/10
Step-by-step explanation:
since
u cross multiply
get -6=60k
=> k = -1/10
Let us assume the first odd integer to be = x
Then
The consecutive middle odd integer = x + 2
The third consecutive odd integer = x + 4
So we can now write the equation as
x + x + 2 + x + 4 = 5(x + 2) - 18
3x + 6 = 5x + 10 - 18
3x + 6 = 5x - 8
3x - 5x = - 8 - 6
- 2x = - 14
2x = 14
x = 14/2
= 7
So the first odd integer is 7
The second consecutive odd integer = (x + 2)
= (7 + 2)
= 9
The third consecutive odd integer = (x + 4)
= 7 + 4)
= 11
So the three consecutive odd integers are 7, 9, 11.
Answer:
x = π/4 - 1/4 sin^(-1)(7/10) + (π n_1)/2 for n_1 element Z
or x = (π n_2)/2 + 1/4 sin^(-1)(7/10) for n_2 element Z
Step-by-step explanation:
Solve for x:
cos(6 x) sin(2 x) - cos(2 x) sin(6 x) = -0.7
-0.7 = -7/10:
cos(6 x) sin(2 x) - cos(2 x) sin(6 x) = -7/10
Reduce trigonometric functions:
-sin(4 x) = -7/10
Multiply both sides by -1:
sin(4 x) = 7/10
Take the inverse sine of both sides:
4 x = π - sin^(-1)(7/10) + 2 π n_1 for n_1 element Z
or 4 x = 2 π n_2 + sin^(-1)(7/10) for n_2 element Z
Divide both sides by 4:
x = π/4 - 1/4 sin^(-1)(7/10) + (π n_1)/2 for n_1 element Z
or 4 x = 2 π n_2 + sin^(-1)(7/10) for n_2 element Z
Divide both sides by 4:
Answer: x = π/4 - 1/4 sin^(-1)(7/10) + (π n_1)/2 for n_1 element Z
or x = (π n_2)/2 + 1/4 sin^(-1)(7/10) for n_2 element Z
