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kaheart [24]
3 years ago
12

6 divided by 2 (1+2) = ?

Mathematics
1 answer:
labwork [276]3 years ago
5 0

Answer:

6/2 (1+2) = 9

Step-by-step explanation:

6/2 (1+2)

Order of operations PEMDAS

Parentheses first 6/2(3)

Multiplication and division go left to right

3(3)=9

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ch4aika [34]
1 of 2 type of lettuces
1 of 4 vegetables
1 of 7 dressings

2*4*7 = 56 different salads
7 0
3 years ago
Will mark brainliest lol​
BabaBlast [244]

Answer:

x=17

The angles are Vertical.

Step-by-step explanation:

6x17 equals 102. Then subtract 12 from 102 to get 90 degrees.

6(17)-12=90 degrees

3 0
3 years ago
Read 2 more answers
If you flip two coins 76 times, what is the best prediction possible for the number of times both coins will land on tails? ​
ioda

Answer:

38 times

Step-by-step explanation:

A coin has two sides, so there is a 50% chance it will land on either side (assuming perfect conditions and that the coin cannot land vertically). With that in mind, if you flip a coin 76 times, 50% or 1/2 of the times the coin should land on tails. That is 36 times. (Once again, this is under perfect testing conditions. In real life, you probably wouldn't get an even split after only 76 flips.)

Hope this helps :)

3 0
2 years ago
Find the volume of the cylinder.
Feliz [49]

Answer:

144pi

Step-by-step explanation:

The formula for the volume of a cylinder is base*height

The base of a cylinder is a circle, so it's pi*r^2

r = 6, so pi*r^2 is 36pi

height is 4 so 36pi*4 is 144pi

8 0
2 years ago
Read 2 more answers
Solve for each system of equations by substitution or elimination.
Tems11 [23]

QUESTION 1

The given system of equations are:

y=x^2+5x+1

y=x^2+2x+1

We equate the two equations to get:

x^2+5x+1 =x^2+2x+1

x^2 -  {x}^{2} + 5x  - 2x = 1 - 1

3x = 0

x = 0

When x=0,

y=0^2+2(0)+1 = 1

The solution is (0,1)

QUESTION 2

The given equations are:

y=x^2-2x - 1

and

y= -x^2-2x-1

We equate both equations to get:

x^2-2x - 1 = -x^2-2x-1

Group similar terms,

x^2 +  {x}^{2} -2x  + 2x= -1 + 1

2 {x}^{2}  = 0

x = 0

We put x=0 into any of the equations to find y.

y= -0^2-2(0)-1 =  - 1

The solution is (0,-1).

QUESTION 3

The given equations are:

y=x^2+2x+1

and

y=x^2+2x-1

We equate both equations:

x^2+2x+1 = x^2+2x-1

Group similar terms:

x^2 -x^2+2x = -1 - 1

0 =  -2

This is not true.

Hence the system has no solution.

6 0
3 years ago
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