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Arlecino [84]
3 years ago
9

A conditional statement p- is true and its converse q- pis false. Which related conditionals are also false?

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
3 0

Answer:

biconditional

Step-by-step explanation:

when are you asked for me thats wrong word bi uncountable only one wright word Conditional

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GIVING BRANLIEST!!!
Anastasy [175]

Answer:

6, 26

Step-by-step explanation:

because x is 6 so itll be -3(6)=-8

-3 times 8 is -26

y=-26

4 0
4 years ago
Solving Rational Functions Hello I'm posting again because I really need help on this any help is appreciated!!​
Greeley [361]

Answer:

x = √17 and x = -√17

Step-by-step explanation:

We have the equation:

\frac{3}{x + 4}  - \frac{1}{x + 3}  = \frac{x + 9}{(x^2 + 7x + 12)}

To solve this we need to remove the denominators.

Then we can first multiply both sides by (x + 4) to get:

\frac{3*(x + 4)}{x + 4}  - \frac{(x + 4)}{x + 3}  = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}

3  - \frac{(x + 4)}{x + 3}  = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}

Now we can multiply both sides by (x + 3)

3*(x + 3)  - \frac{(x + 4)*(x+3)}{x + 3}  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}

3*(x + 3)  - (x + 4)  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}

(2*x + 5)  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}

Now we can multiply both sides by (x^2 + 7*x + 12)

(2*x + 5)*(x^2 + 7x + 12)  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}*(x^2 + 7x + 12)

(2*x + 5)*(x^2 + 7x + 12)  = (x + 9)*(x + 4)*(x+3)

Now we need to solve this:

we will get

2*x^3 + 19*x^2 + 59*x + 60 =  (x^2 + 13*x + 3)*(x + 3)

2*x^3 + 19*x^2 + 59*x + 60 =  x^3 + 16*x^2 + 42*x + 9

Then we get:

2*x^3 + 19*x^2 + 59*x + 60 - (  x^3 + 16*x^2 + 42*x + 9) = 0

x^3 + 3x^2 + 17*x + 51 = 0

So now we only need to solve this.

We can see that the constant is 51.

Then one root will be a factor of 51.

The factors of -51 are:

-3 and -17

Let's try -3

p( -3) = (-3)^3 + 3*(-3)^2 + +17*(-3) + 51 = 0

Then x = -3 is one solution of the equation.

But if we look at the original equation, x = -3 will lead to a zero in one denominator, then this solution can be ignored.

This means that we can take a factor (x + 3) out, so we can rewrite our equation as:

x^3 + 3x^2 + 17*x + 51 = (x + 3)*(x^2 + 17) = 0

The other two solutions are when the other term is equal to zero.

Then the other two solutions are given by:

x = ±√17

And neither of these have problems in the denominators, so we can conclude that the solutions are:

x = √17 and x = -√17

6 0
3 years ago
Translate the algebraic expression shown below into a verbal expression.
yaroslaw [1]
The quotient of some number and four.
6 0
3 years ago
Use a graphing calculator to sketch the graph of the quadratic equation, and then state the domain and range. y=-5x^2+3x+10
Bond [772]

Answer:

The answer to your question is:

Domain: (-∞, ∞)

Range: [10, ∞)

Step-by-step explanation:

Data

Graph                                 y = 5x² + 3x + 10

Process

As it is suggested, let's use a graphing calculator. But we can sketch that because it is a quadratic equation, then the graph will be a parabola that opens upwards.

See the graph below.

Domain: are the possible values of the independent variable.

Range: are the reslunting values of the dependent variable.

Then

Domain : (- ∞, ∞)             It is an  open interval because -∞ and ∞ are

                                       not included.

Range : [10, ∞)                It is close because 10 is included.

3 0
3 years ago
1/4 X Plus x equals negative 3 plus 1/2 x
ElenaW [278]
1/4x+4/4x = -6/2x+1/2x
5/4x = -5/2x
x=0
5 0
3 years ago
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