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Alona [7]
3 years ago
9

Maria has a box of 20 cookies. She gives 2 cookies to each friend. Which expression shows the number of cookies Maria has left a

fter giving cookies to m friends?
A. 2m - 20
B. 20 - 2m
C. 20m - 2
D. 20 + 2m
Mathematics
2 answers:
eimsori [14]3 years ago
8 0
B. 20-2m would be the correct equation!
Anvisha [2.4K]3 years ago
5 0
B is the correct answer
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If x to the second power equals 20 what is the value of x?
fiasKO [112]

Hey there!


Let's set up an algebraic equation to represent this problem:


x^2=20


In order to get rid of the squared, we need to take the square root of both sides, therefore, our answer is:


x= \sqrt{20}


Your answer is the square root of 20.


Hope this helps!

5 0
3 years ago
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5/6-1/3= (reduced form please)
Masteriza [31]
The correct answer is 0.5 as a decimal as a fraction it is 5/10 = 1/2 so it is what ever one u need 1/2 or 5/10 or 0.5. Hope this helps! ;D
7 0
2 years ago
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Find the value of x to the nearest tenth.
Blababa [14]

Answer:

59.3

Step-by-step explanation:

tanx=54/32

tanx=59.3

5 0
1 year ago
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Draw 8 lines that are between 1 inch and 3 inches long measure each line to the nearest fourth inch and make a line plot
Paraphin [41]
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6 0
3 years ago
Find all the zeros for each function P(x)=x^4-4x^3-x^2+20x-20
ivanzaharov [21]

Answer:

The zeros of the given polynomial function are

2,2,\pm\sqrt{5}

Step-by-step explanation:

Given polynomial is P(x)=x^4-4x^3-x^2+20x-20

To find the zeros equate the given polynomial to zero

ie., P(x)=0

P(x)=x^4-4x^3-x^2+20x-20=0

By using synthetic division we can solve the polynomial:

2_|   1     -4     -1      20      -20

       0      2     -4     -10       20

   _____________________

       1     -2      -5      10      |_0

Therefore x-2=0

x=2 is a zero of P(x)

Now we can write the cubic equation as below:

x^3-2x^2-5x+10=0

Again using synthetic division

2_|   1     -2     -5     10      

       0      2      0    -10    

    ______________

       1      0      -5     |_0

Therefore x-2=0

x=2 is also a zero of P(x).

Now we have x^2+0x-5=0

x^2-5=0

x^2=5

x^=\pm\sqrt{5} is a zero of P(x)

Therefore the zeros are 2,2,\pm\sqrt{5}

8 0
3 years ago
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