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Alenkasestr [34]
3 years ago
14

Find each product (x+5)(x-5)

Mathematics
1 answer:
Alina [70]3 years ago
5 0

x^2-25

(x+5)(x-5)

x^2-5x+5x-25

x^2-25

hopes this helps,

Xeno

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Is 86, 75, 97, 58. 94, and 58, odd or even
alexira [117]
This is even because they all can be divided if it was odd you would not be able to decide them
5 0
3 years ago
An arc with length 5 pi over 4 inches is formed by a 15 degree central angle what is the radius of the circle
Natalka [10]

Answer:

Radius of the circle is <em>15 inches.</em>

<em></em>

Step-by-step explanation:

Relation between length of arc, radius and the angle subtended by the arc on center is:

\theta = \dfrac{l}{r} ..... (1)

where \theta is the central angle in radians subtended by arc

l is the length of arc

r is the radius of arc

We are Given the following details:

l = \dfrac{5\pi}{4}\ inch

\theta = 15^\circ

We know that \pi \ radians = 180 ^\circ

Converting \theta to radians:

\theta =\dfrac{\pi}{180} \times 15 radians

Putting the values of \theta and l to find the value of r

\dfrac{\pi}{180} \times 15 = \dfrac{5\pi}{4r}\\\Rightarrow r = \dfrac{45}{3} \\\Rightarrow r = 15 \ inches

Hence, Radius of the circle is <em>15 inches.</em>

6 0
2 years ago
The discriminant of the equation x^2 - 4x + 4 = 0 shows there will be solution(s).
Alex787 [66]

Answer:

one real

Answer: 1

Step-by-step explanation:

Givens

a = 1

b = -4

c = 4

Discriminate

Discriminate = sqrt(b^2 - 4*a*c)

Discriminate  = sqrt(  (-4)^2 - 4 * (1)(4) )

Discriminate = sqrt ( 16 - 16)

Discriminate = sqrt(0)

Discriminate = 0

That means the 1 real root is -  b / 2a = 4/(2*1) = - -2 = 2

3 0
2 years ago
Write an expression for a number that is 5 times greater than 2
ElenaW [278]

Answer:

x = 5x > 2

or just 5x > 2 ya its that

Step-by-step explanation:

4 0
3 years ago
The sum of a rational number and negative integer is rational
natulia [17]

Answer:

correct

Step-by-step explanation:

negative integers are still rational numbers if it is a whole number or complete

4 0
3 years ago
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