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Alenkasestr [34]
3 years ago
14

Find each product (x+5)(x-5)

Mathematics
1 answer:
Alina [70]3 years ago
5 0

x^2-25

(x+5)(x-5)

x^2-5x+5x-25

x^2-25

hopes this helps,

Xeno

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Which of these limits evaluate to 0?
Vikentia [17]
<h3>Answer: C) I and II only</h3>

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Work Shown:

Part I

\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\

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Part II

\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\

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Part III

\displaystyle \lim_{x \to 5}\frac{x}{x} = \lim_{x \to 5}1\\\\\\\displaystyle \lim_{x \to 5}\frac{x}{x} = 1\\\\\\

7 0
3 years ago
If location a is 87.2 f and location b is 30.3c which is the warmer temperature and by how much
dlinn [17]

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Step-by-step explanation:

3 0
3 years ago
In a triangle, find the value of the remote exterior angle given the remote interior angles are 27 and 53 degrees
GenaCL600 [577]

Answer:

80°

Step-by-step explanation:

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5 0
3 years ago
There were 462 people sitting in the audience. Round the number of people to the nearest hundred.
Pavel [41]
500
Sorry if its wrong
4 0
3 years ago
Algebra problem!!! Please help me!!!
zmey [24]

Good morning Brainiac

x+y = 13

1/2 x +y = 10


We gonna solve x+y=13 for x

So let's start by adding -y to both sides

x+y -y = 13-y

x= -y +13

Now substitute -y+13 for x in 1/2 x +y=10

1/2 x +y = 10

1/2 (-y+13)+y=10

1/2 y + 13/2 = 10

Now add -13/2 to both sides

1/2 y+13/2 -13/2 = 10- 13/2

1/2 y = 7/2

Now eliminate the common denominator which is 2

y = 7

Now we have the value for y, so lets find the value for x by substitute 7 for y in x= -y+13

x= -y+13

x= -7 + 13

x= 6

Answer : (6,7)

The answer is B


I hope that's help and if you have questions please let me know :)


Good luck

3 0
3 years ago
Read 2 more answers
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