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solmaris [256]
3 years ago
10

Please help me im horrable at math

Mathematics
1 answer:
Masja [62]3 years ago
7 0

1.) First plug in the values for m and A:

2555 = 139(4) + b

--> 2555 = 556 + b

Isolate b: 2555 - 556 = 556 - 556 + b

b = 1999

So your answer is the first option.

2.) Admission costs $5.25, so even if you don't go on any rides, you will still have to pay $5.25. This means that for this problem, 5.25 will be the b value. If each ride costs $2.50, then this means it is $2.50x for the cost of x rides. The total cost will then be C = 5.25 + 2.50x.

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Please help with these 3 questions
Sever21 [200]

Answer: x = 11

Step-by-step explanation:

2x+5 = 3x-6

2x-3x = -6-5

-x = -11

x = 11

Double-check:
11*2= 22                   11*3=33

22+5 = 27                33-6= 27

4 0
2 years ago
On a coordinate plane, how are the locations of the points (-4 , 8) and (-4 , -8) related?
STALIN [3.7K]

Answer:

A. reflection across the y-axiss

Step-by-step explanation:

Given:

The locations of the two points are (-4 , 8) and (-4 , -8).

To find:

The relation between two points.

From the given points (-4, 8) and (-4 , -8), it is clear that the y-coordinates are same but the sign of x-coordinates are opposite.

If a figure is reflected across the y-axis, then we change the sign of x-coordinate and the y-coordinates remain same, i.e.,

(x,y)→(-x,y)

For (-4,8)

(-4,8)→ (-4,-8)

So, it is reflection across the y-axis.

Therefore, the correct option is A.

6 0
3 years ago
Find the annual interest rate. I=$16I=$16, P=$200P=$200, t=2t=2 years
BigorU [14]
R=i/pt
R=16/200*2=0.04*100=4%
3 0
3 years ago
If f(x) = 2x^3 - 14x^2 + 38x -26 and x-1 is a factor of f(x) find all of the zeros of f(x) algebraically.
Anestetic [448]

Answer:

Step-by-step explanation:

First confirm that x = 1 is one of the zeros.

f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26

f(1) = 2 - 14 + 38 - 26

f(1) = -12 + 38 = + 26

f(1) = 26 - 26

f(1) = 0

=========================

next perform a long division

x -1  || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26

          2x^3 - 2x^2

          ===========

                    -12x^2 + 28x

                     -12x^2 +12x

                     ==========

                                  26x -26

                                  26x - 26

                                 ========

                                      0

Now you can factor 2x^2 - 12x + 26

                                 2(x^2 - 6x + 13)

The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16

So you are going to get a complex result.

x = -(-6) +/- sqrt(-16)

     =============

                 2

x  = 3 +/- 2i

f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)

The zeros are

1

3 +/- 2i

8 0
3 years ago
PLEASE HELP ASAP!!!!!!!! I ONLY HAVE 20 MORE MINUTES AND I HAVE LIKE EIGHT MORE QUESTIONS!!!
sertanlavr [38]

Answer:

I'm pretty sure its -4-12x but I could be wrong

Step-by-step explanation:

First I tried to solve for x but got -12x+4 so to get 4 on the other side of the equation I subtracted and got -4-12x I hope this helps :)

7 0
3 years ago
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