Answer:
Cardiovascular system
Step-by-step explanation:
Solution :
Mean time for an automobile to run a 5000 mile check and service = 1.4 hours
Standard deviation = 0.7 hours
Maximum average service time = 1.6 hours for one automobile
The z - score for 1.6 hours = 
= 2.02
Now checking a normal curve table the percentage of z score over 2.02 is 0.0217
Therefore the overtime that will have to be worked on only 0.217 or 2.017% of all days.
First let’s find the equation:
a = (42-21)/(26-13)
a= 21/13
y-y1 = a(x-x1)
y-21=(21/13)(x-13)
y-21=(21/13)x - 21
y=(21/13)x-21+21
y=(21/13)x
Now we will find the other point:
X = 2 >> y =(21/13)*2 = 3.23 (not)
X = 3 >> y =(21/13)*3 = 4.84 (not)
X = 4 >> y =(21/13)*4 = 6.46 (not)
X = 5 >> y =(21/13)*5 = 8.07 (yes) find the answer