Answer:
3
Explanation:
Here's the balanced equation;
C2H4 + 3O2 → 2CO2 + 2H2O
C ⇒2 C ⇒1 x 2 = 2
H ⇒4 H ⇒2 x 2 = 4
O ⇒3 x 2 = 6 O ⇒ (2 x 2) + (2 x 1) = 6
Answer: -112200J
Explanation:
The amount of heat (Q) released from an heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Since,
Q = ?
Mass of water vapour = 30.0g
C = 187 J/ G°C
Φ = (Final temperature - Initial temperature)
= 100°C - 120°C = -20°C
Then apply the formula, Q = MCΦ
Q = 30.0g x 187 J/ G°C x -20°C
Q = -112200J (The negative sign does indicates that heat was released to the surroundings)
Thus, -112200 joules of heat is released when cooling the superheated vapour.
Answer:
The Correct IUPAC name is H3C - CH (CH3) - CH (C2H5) - (CH2)2 - CH3 Class 11
Explanation:
ye thiss right it only show this for me like or star or comment if right all is good idc tell me if u got it
Answer:
The answer to your question is 178.6 g
Explanation:
Data
ΔT = 1.8 °C
mass = 17.5 g
mass of water = 100 g
Kc = 1.86
Process
1.- Calculate the molality using the following formula
ΔTc = mKc
solve for m
m = ΔTc/Kc
substitution
m = 1.8/1.86
result
m = 0.968
2.- Calculate the number of moles
m = # of moles/kg of solvent
kg of solvent = 0.1 kg
# of moles = m x kg of solvent
# of moles = 0.968 x 0.1
# of moles = 0.0968
3.- Calculate the molar mass
x g molar mass --------------------- 1 mol
17.5 g --------------------- 0.0968 moles
x = (1 x 17.5)/0.0968
x = 178.6 g
Answer:
yes. you need blood to live. if it runs low then your life starts to disappear just like the river would if the water started to run low in it
