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Anarel [89]
3 years ago
14

You invest $25/month at a rate of 3.25% APR compounded monthly for 30 years. What is the total interest earned and final balance

?
Mathematics
1 answer:
VikaD [51]3 years ago
7 0

The total interest earned is 40.75 and the final balance is 65.75

<u>Solution:</u>

Given, principle amount P = 25

Interest rate r = 3.25\% = \frac{3.25}{100} = 0.0325

Times compounded per year n = 12

Time in years t = 30

Amount \ A=P\left(1+\frac{r}{n}\right)^{n t}

On substituting the values we get

A = 25 [ 1+ \frac{0.0325}{12}]^{12\times30}= 25 [2.63]= 65.75

Interest I = A - P [since, A = P+I]

\Rightarrow 65.75 - 25= 40.75

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Carmen bought a desktop computer and a laptop computer. Before finance charges, the laptop cost $200 less than the desktop. She
stiks02 [169]
Let x = cost of desktop computer; then x - 250 = cost of laptop computer

converting % to decimals, 9% = 0.09 and 6% = 0.06

Then, 0.09x + (x - 250)0.06 = $300
0.09x + 0.06x - 15 = $300
0.15x = $315
x = $2100
then x - 250 = $1850

Proof: $2100•0.09 + 1850•0.06 = $189 + $111 = $300
5 0
2 years ago
What is the coefficient of the variable in the expression 6-4x-8x+2
Daniel [21]

I think the trick is to add the two middle terms together.  (And the 2 end terms).

8 - 12x

The variable is x. The coefficient is - 12.

8 is a constant.

The coefficient always goes with a variable.

3x^2 + 2x + 5

Nothing can be combined.  The leading coefficient is 3 (which goes with the greatest power of the variable x^2 in this case) and the other coefficient is 2. 5 is a constant.  

6 0
3 years ago
A population of 240 birds increases at a rate of 16% annually. Jemel writes an exponential function of the form f(x) = abx to re
d1i1m1o1n [39]
An exponential function is :
f ( x ) = a * b^x,
where x is the number of the years.
a = 240   ( number of the birds at start )
16 % = 0.16
b = 1 + 0.16 = 1.16
f ( x ) = 240 * 1.16^x
Answer:
a = 240,   b = 1.16
7 0
3 years ago
Read 2 more answers
Determine if the following are in proportion :
KATRIN_1 [288]

Step-by-step explanation:

The given numbers are : 32 , 48 , 140 , 120

First number is 32

Second number is 48

Third number is 140

Fourth number is 120

First number/second number :

\dfrac{N_1}{N_2}=\dfrac{32}{48}\\\\=\dfrac{2}{3}\ ....(1)

Third number/Fouth number :

\dfrac{N_3}{N_4}=\dfrac{140}{120}\\\\=\dfrac{7}{6}\ ....(2)

From equation (1) and (2) we can see that the ratio is not same. Hence, they are not in proportion.

3 0
3 years ago
A trucking firm suspects that the mean life of a certain tire. it uses is less than 33,000 miles. To check the claim, the firm r
Mice21 [21]

Answer:

We accept the alternate hypothesis. We conclude that the mean lifetime of tires is  is less than 33,000 miles.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 33,000 miles

Sample mean, \bar{x} =  32, 450 miles

Sample size, n = 18

Alpha, α = 0.05

Sample standard deviation, s = 1200 miles

a) First, we design the null and the alternate hypothesis

H_{0}: \mu = 33000\text{ miles}\\H_A: \mu < 33000\text{ miles}

b) Level of significance:

\alpha = 0.05

c) We use One-tailed t test to perform this hypothesis.

d) Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{32450 - 33000}{\frac{1200}{\sqrt{18}} } = -1.9445

Now, t_{critical} \text{ at 0.05 level of significance, 17 degree of freedom } = -1.7396

Rejection area:

t < -1.7396

Since,                  

t_{stat} < t_{critical}

e) We fail to accept the null hypothesis and reject it as the calculated value of t lies in the rejection area.

f) We accept the alternate hypothesis. We conclude that the mean lifetime of tires is  is less than 33,000 miles.

3 0
3 years ago
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