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mote1985 [20]
3 years ago
6

When all the variables cancel out in an equation, how do you know if there are no solutions or infinite solutions?

Mathematics
1 answer:
Ivahew [28]3 years ago
4 0
If a number equals the same number, there are infinite solutions
Example: 5=5, which is true, so there are infinite solutions
If a number equals a different number, there are no solutions
Example: 5=2, which isn’t true
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How would i anser this select all the ratios equivalent to 4:6
Natali5045456 [20]
If we try to simplify the ratio or try to multiply both by any number, we will get the equivalent ratio


Like :

\frac{4}{6}  \\


Divide ( simplify ) by 2


\frac{ \frac{4}{2} }{ \frac{6}{2} }  \\  \\  \\  =  >  \frac{2}{3}




Or multiply by any number,



\frac{4}{6}  \\  \\  \\  =  >  \frac{4 \times 2}{6 \times 2}  \\  \\ \\    =  >  \frac{8}{12}





From the example, 2 / 3 and 8 / 12 are equivalent ratios to 4 / 6
6 0
3 years ago
Please help me with this question
san4es73 [151]

Step-by-step explanation:

Given: f'(x) = x^2e^{2x^3} and f(0) = 0

We can solve for f(x) by writing

\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx

Let u = 2x^3

\:\:\:\:du=6x^2dx

Then

\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du

\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k

We know that f(0) = 0 so we can find the value for k:

f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}

Therefore,

\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)

5 0
3 years ago
Please answer correctly !!!!!!! Will mark brainliest answer !!!!!!!!
Allisa [31]

Answer:

A is the answer i believe

Step-by-step explanation:

3 0
3 years ago
14. Which of the following is true about given APQR given in Figure 7.82 to the right? a. p²+q²=² b. q²+r²=p² c. (p+q)²=r² d. p²
Cloud [144]
Answer :
a. p²+q²=r²

According to the Pythagorean theorem :
p²+q²=r² ,because this is a right triangle and r is the length of the hypotenuse.
8 0
2 years ago
Ratios equivalent to 10:9.
Aleks04 [339]

Answer:20:18

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
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