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BlackZzzverrR [31]

3 years ago

8

Which of these forces is acting on a baseball sitting on level ground? A. applied force B. frictional force C. gravitational for

ce

2 answers:

aksik [14]3 years ago

8 0

C.) Gravitational Force

snow_lady [41]3 years ago

4 0

C. gravitational force

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What is the correct IUPAC name for Al(IO₃)₃?

Marysya12 [62]

Answer:

Aluminum Iodate

7 0

3 years ago

A compound has a percent composition of 40.0% carbon , 6.72% hydrogen , and 53.28% oxygen . If it's molar mass is 180 g/mol , wh

yan [13]

1) Molar composition

Base: 100 g

C: 40.00 g / 12.0 g /mol = 3.333 mol

H: 6.72 g / 1 g/mol = 6.72 mol

O: 53.28 g / 16g/mol = 3.33 mol

2) Divide by the smaller number of moles

C: 3.333 / 3.33 = 1.00

H: 6.72 / 3.33 = 2.02 ≈ 2

O: 3.33/3.33 = 1.00

3) Empirical formula

CH2O

molar mass of the empirical formula = 12 g/mol + 2*1g/mol + 16 g/mol = 30 g/,ol

4) Number of times that the mass of empirical formula is contained in the molar mass = 180 g/mol / 30 g/mol = 6

5) Molecular formula = 6 times the empirical formula

=>C6H12O6

Answer: C6H12O6

6 0

3 years ago

If you need 0.0592 moles of nitrogen, how many grams of nitrogen do you need to mass(weigh) on the

navik [9.2K]

Urchin tc yc you txutxurzyrxtuciyvuoxutxurx

8 0

3 years ago

What was different about the atomic theory proposed by niels bohr? A positively charged nucleus in the center of the atom electr

olga_2 [115]

Answer:

The correct answer would be B, electrons energy levels related to their orbits.

Explanation:

I hope this helps you!

8 0

3 years ago

A container of carbon dioxide (CO2) has an initial temperature of 170 K with a pressure of 50 kPa. When the container is heated

Bond [772]

Answer: T2= 962.2 K

Explanation:

The ideal gases is often written like PV=nRT, where P is pressure, V is volume, n is moles, R is the universal constant of the gases and T is Temperature.

So, in this problem there is a container that is a closed system, therefore n is constant and volume too. The initial point is 1 and the final point is 2, so

V1=V2 ⇒

$\frac{n1RT1}{P1} = \frac{n2RT2}{P2} \\\\\frac{T1}{P1} = \frac{T2}{P2} \\\\T2= \frac{T1P2}{P1} =\frac{170 K 283KPa}{50 KPa} =962.2 K$

5 0

3 years ago