The empirical formula :
C₁₀H₁₆N₄SO₇
<h3>Further explanation</h3>
Given
6.4 g sample
Required
The empirical formula
Solution
mass C :
= 12/44 x 8.37 g
= 2.28
mass H :
= 2/18 x 2.75 g
= 0.305
mass N = 1.06
mass S :
= 32/64 x 1.23
= 0.615
mass O = 6.4 - (2.28+0.305+1.06+0.615) = 2.14 g
Mol ratio :
= C : H : N : S : O
= 2.28/12 : 0.305/1 : 1.06/14 : 0.615/32 : 2.14/16
= 0.19 : 0.305 : 0.076 : 0.019 : 0.133 divided by 0.019
= 10 : 16 : 4 : 1 : 7
The empirical formula :
C₁₀H₁₆N₄SO₇
Answer:
CH₄ will diffuse at faster rate.
Explanation:
According to Graham's law,
The rate of diffusion is inversely proportional to the square root of molar mas of gas.
It is given in question the molar mass of CH₄ is 16 g. Thus the square rot of 16 is.
√16 = 4
The molar mass of SO₂ is 64 g and the square root is,
√64 = 16
As it is stated that diffusion rate is inversely related to the square root of molar mass thus the diffusion rate of SO₂ is lower while methane diffuse faster.
Answer: G Atom 1 and Atom 4.. hope this helps and good luck!
Because the temperature and pressure are not below 100c or above 100000KPa
Answer:
46 hours
Explanation:
you're walking four miles per hour and you walked 11 and a half hours so if you multiply four by eleven and a half you will get 46
