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Alex_Xolod [135]
3 years ago
13

β-Myrcene, a key intermediate in the production of several fragrances, is 7-methyl-3-methylene-1,6-octadiene.Draw the structure

of this triene.
Chemistry
1 answer:
sdas [7]3 years ago
3 0

Answer:

this is the structure of beta myrcene but im notsure which structure you were looking for

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PLEASE PLEASE HELP ME!!!A 450 ml gas sample has a pressure of 1.25 atm at 65 °C. What is the temperature, in °C, at which the ga
Arlecino [84]

Answer:

89°C

Explanation:

Combined Gas Law (P₁V₁)/T₁ = (P₂V₂)/T₂

(1.25 atm)(450 mL)/(65°C) = (0.89 atm)(865 mL)/T₂

8.653846154 = 769.85/T₂

T₂ = 769.85/8.653846154

T₂ = 88.96044444 = 89°C

6 0
2 years ago
How many cm 3 are in 0.14 m 3?
nlexa [21]

Answer:

There are 14 cm in 0.14 m

5 0
3 years ago
Desiré was investigating a chemical reaction.When she heated it up, she found that sulfuric acid changed into water. She made th
pochemuha

Answer:

no it is not a complete model

3 0
3 years ago
In a 0.20 M solution, a weak acid is 3.0% dissociated.(a) Calculate the [H₃O⁺] , pH , [OH⁻], and pOH of the solution.
marin [14]

H₃O⁺ = 6.0×10^{-3}

OH = 1.7×10^{-12}

pH = 2.22

pOH = 11.78

<h3>What is pH?</h3>

The term pH, which originally stood for "potential of hydrogen" (or "power of hydrogen"), is used in chemistry to describe how acidic or basic an aqueous solution is. Lower pH values are summarized for acidic solutions (solutions with higher H+ ion concentrations) than for basic or alkaline solutions.

The pH scale is inversely indicates to the concentration of hydrogen ions in the solution and is logarithmic.

⇒pH = -log(a_{H+})

Acidic solutions are those with a pH below 7, and basic solutions are those with a pH above 7, at a temperature of 25 °C (77 °F). At this temperature, solutions with a pH of 7 are neutral (e.g. pure water). The pH neutrality relies on temperature, falling below 7 if the temperature rises above 25 °C.

Learn more about pH

brainly.com/question/12609985

#SPJ4

8 0
2 years ago
Help and show work please
olya-2409 [2.1K]
ANWERS ~
We know that :
1 cal (th) = 4.184 J
1 J = 0.2390057361 cal (th) , so :

•55.2 j to cal > 13.193116635 cal
•110 call > 460.24 joule
•65 kj > divide the energy value by 4.184
= 15.535 kilocalories calorie (IT)
——————
Converting form C to F > (F-32)*5/9Understand it better if we have Fahrenheit just add to the equation mentioned to find Celsius.
+to find F to C> (9/5*C)+32

•425 Fahrenheit = (425- 32) × 5/9 =218.33333333 Celsius

•1935 C = 3515 F
———————————-
Converting Celsius to kelvin,We know that :
K = C + 273.15
C = K - 273.15
And from F to K=9/5(F+459.67)
And K to F =(9/5 *k)-459.67
•39.4 Celsius = 312.55 kelvin
•337 Fahrenheit = (337+ 459.67) × 5/9 =442.594 kelvin





4 0
3 years ago
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