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Maurinko [17]
3 years ago
10

A line has slope 5/6 and y-intercept-3

Mathematics
1 answer:
viva [34]3 years ago
8 0

Answer:

The equation would be y = 5/6x - 3

Step-by-step explanation:

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Why has it been difficult to pass laws regarding transportation?
Rzqust [24]

Answer:

a-it would cause too much of a tax increase

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3 years ago
WILL CHOOSE BRAINLIEST!!! The oxford square is approximately 300 feet on each side. What is the length of the diagonal square?
Marina CMI [18]

Answer:

424 ft and 3 inches

Step-by-step explanation:

To calculate the diagonal of a square, multiply the length of the side by the square root of 2 --> d = a√2

a² + a² = diagonal²

diagonal = √(a² + a²) = √(2 x a²) which simplifies to diagonal = a√2

If area is given --> d = √(2*area)

Knowing square perimeter --> d = (perimeter/4)*√2

5 0
2 years ago
Read 2 more answers
A researcher plans to study the causal effect of a strong legal system on economy, using data from a random sample of U.S. count
kogti [31]

Answer:

Based on expert opinion the regression does not suffer from omitted variable bias

Step-by-step explanation:

<em>Based on expert opinion the regression does not suffer from omitted variable bias </em>because its indicators taking values of 1 and 0 where 1 would represent taking action by the legal system  and 0 would represent not taking action by the legal system. as

The researcher plans to regress national income per capita based on the effect of the legal system

applying the formula for addressing omitted variable bias ( attached below )

7 0
3 years ago
A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In
lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

                        P.Q. = \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }  ~ N(0,1)

where, \hat p_1 = sample proportion of males having blood disorder= \frac{250}{1000} = 0.25

\hat p_2 = sample proportion of females having blood disorder = \frac{275}{1000} = 0.275

n_1 = sample of males = 1000

n_2 = sample of females = 1000

p_1 = population proportion of males having blood disorder

p_2 = population proportion of females having blood disorder

<em>Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.</em>

<u>So, 95% confidence interval for the difference between the population proportions, </u><u>(</u>p_1-p_2<u>)</u><u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                             of significance are -1.96 & 1.96}  

P(-1.96 < \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < {(\hat p_1-\hat p_2)-(p_1-p_2)} < 1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

P( (\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < (p_1-p_2) < (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

<u>95% confidence interval for</u> (p_1-p_2) =

[(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }, (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }]

= [ (0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }, (0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} } ]

 = [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0
3 years ago
Andrew
PilotLPTM [1.2K]
Let's say Bailey takes "b" days to paint it.

and Andrew takes "a" days to paint the same house.

now, Andrew is 6 times faster than Bailey, therefore, if Andrew takes "a" days to do it, Bailey takes then "6a" days, or b = 6a.

now, the year they worked together, they finished it in 7 days.

so, after 1 day then, they have only done 1/7 of the whole work.

and Andrew for one day, has done 1/a of the house, whilst Bailey has done 1/b of the house or 1/(6a).

\bf \stackrel{\textit{Andrew's rate}}{\cfrac{1}{a}}+\stackrel{\textit{Bailey's rate}}{\cfrac{1}{b}}=\stackrel{\textit{1 day of work}}{\cfrac{1}{7}}&#10;\\\\\\&#10;\cfrac{1}{a}+\cfrac{1}{6a}=\cfrac{1}{7}\impliedby &#10;\begin{array}{llll}&#10;\textit{let's multiply all by }\stackrel{LCD}{42a}\textit{ to toss the}\\&#10;denominators&#10;\end{array}

\bf 42a\left( \cfrac{1}{a}+\cfrac{1}{6a} \right)=42a\left( \cfrac{1}{7} \right)\implies 42+7=6a\implies \cfrac{49}{6}=a&#10;\\\\\\&#10;\stackrel{days}{8\frac{1}{6}}=a&#10;\\\\\\&#10;\textit{how many days will it take Bailey then?}\quad b=6a&#10;\\\\\\&#10;b=6\cdot \cfrac{49}{6}\implies b=\stackrel{days}{49}
6 0
4 years ago
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