Answer:
0.3m
Explanation:
Given parameters;
Elastic energy = 20J
Spring constant = 445N/m
Unknown
Final extension of the spring = ?
Solution:
The elastic potential energy of a stretched spring can be determined using the expression below;
EP = 
k e²
k is the spring constant
e is the extension
Insert the parameters and solve;
20 = x 445 x e²
multiply those sides by 2;
2(20) = 445e²
40 = 445e²
e² = 
= 0.09
e = √0.09 = 0.3m
Answer:
Option A
D = m/v
Explanation:
Density is defined as mass per unit volume of an object. Therefore, D=m/v where m is the mass of the object and v is the volume
Therefore, option A is the right option
Answer:
A
Explanation:
Forces are vector quantities because they have both magnitude and direction.
Answer:103 pounds
Explanation:
Given
width of window 
height of window 
standard atmospheric pressure 
Also 
Thus Net Force on the window will be the algebraic sum of Force due to outside and inside Pressure .
