It would be 27.5 miles per gallon
Logitudinal waves are the waves which displacement of the medium is in the same direction as , or oppositemdirection to ,the direction of propagation of the wave.
Answer:
A. Normal force is always perpendicular to the area of contact between an object and support.
Explanation:
Normal force is defined as the contact force. If there is no contact between the surfaces, they cannot applies a force which is normal on each other. For e.g, the surfaces of a cubical box and the cart cannot applies a force of normal on each other because of no contact.
If, when there is a contact between two surfaces they applies a normal force on each other, and this force is perpendicular to the each other . This normal force is necessary to prevent object to penetrating into other.
Answer:
0.12
Explanation:
The acceleration due to gravity of a planet with mass M and radius R is given as:
g = (G*M) / R²
Where G is gravitational constant.
The mass of the planet M = 3 times the mass of earth = 3 * 5.972 * 10^24 kg
The radius of the planet R = 5 times the radius of earth = 5 * 6.371 * 10^6 m
Therefore:
g(planet) = (6.67 * 10^(-11) * 3 * 5.972 * 10^24) / (5 * 6.371 * 10^6)²
g(planet) = 1.18 m/s²
Therefore ratio of acceleration due to gravity on the surface of the planet, g(planet) to acceleration due to gravity on the surface of the planet, g(earth) is:
g(planet)/g(earth) = 1.18/9.8 = 0.12
Answer:
a) Ffloor = 616.56[N]
b) Ffloor = 484.16 [N]
Explanation:
In order to solve this problem, we must first make a free body diagram. In this free body diagram include forces, as well as acceleration.
Then after the free body diagram, we perform a force analysis by means of Newton's second law, where the upward forces and even the upward acceleration will be taken as positive.
ΣF = m*a
where:
F = force [N] (units of Newtons]
m = mass [kg]
a = acceleration [m/s²]
g = gravity acceleration = 9,81 [m/s²]
a)

![F_{floor} -(56*9.81)=56*1.2\\F_{floor}= 616.56[N]](https://tex.z-dn.net/?f=F_%7Bfloor%7D%20-%2856%2A9.81%29%3D56%2A1.2%5C%5CF_%7Bfloor%7D%3D%20616.56%5BN%5D)
b) Using Newton's second law we have.
![F_{floor}-m*g= -m*a\\F_{floor}=-m*a+m*g\\F_{floor} = -(56*1.2) + (56*9.81)\\F_{floor} = 484.16 [N]](https://tex.z-dn.net/?f=F_%7Bfloor%7D-m%2Ag%3D%20-m%2Aa%5C%5CF_%7Bfloor%7D%3D-m%2Aa%2Bm%2Ag%5C%5CF_%7Bfloor%7D%20%3D%20-%2856%2A1.2%29%20%2B%20%2856%2A9.81%29%5C%5CF_%7Bfloor%7D%20%3D%20484.16%20%5BN%5D)