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Readme [11.4K]
3 years ago
15

when white light is incident on prism, which one of the resulting color components will have the lowest index of refraction?

Physics
2 answers:
Anni [7]3 years ago
6 0
<h2>Answer:</h2>

<u>Red color</u><u> has the lowest index of refraction</u>

<h2>Explanation:</h2>

In the spectrum of visible light we can observe that red is at the top and violet is at the bottom. Since v = λ . f , where is the wave velocity, is the frequency and is the wavelength of the wave so we can say that red is less deviated than violet. Therefore red has the lowest refractive index among the colors in “VIBGYOR Pattern”.

attashe74 [19]3 years ago
3 0
The color components that will have the lowest index of refraction will be orange.
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Answer:

The value is  \rho_s  =  4.026 *10^{-6} \  C/m^2

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From the question we are told that

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    The radius of the outer conductor is  r_2 = 3 \ mm = 0.003 \  m

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      C= \frac{2 * \pi * \epsilon_o }{ ln [\frac{r_2}{r_1} ]}

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=>   C= 50.6 *10^{-12} \  F/m

Generally given that the potential  of the outer conductor with respect to the inner conductor is positive it then mean that the outer conductor is positively charge

Generally the line  charge density of the outer  conductor is mathematically represented as

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=>   \rho_d  =  50.6*10^{-12} *  1.5*10^{3}

=>   \rho_d  =  7.59*10^{-8} \  C/m

Generally the surface charge density is mathematically represented as

        \rho_s  =  \frac{\rho_l }{2 \pi * r_2 }    here 2 \pi r = (circumference \ of \ outer \  conductor  )

=>    \rho_s  =  \frac{7.59 *10^{-8} }{2* 3.142 * 0.003 }

=>    \rho_s  =  4.026 *10^{-6} \  C/m^2

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