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2 years ago

HELWP MWEEEEEEEEEEEEEEE

Mathematics

2 answers:

tiny-mole [99]2 years ago

4 0

1440 is the answer I think

OverLord2011 [107]2 years ago

4 0

A = $1,120 B = $5120

Step-by-step explanation:

1.4/100 = 0.014

0.014 x 4000 = 56

1.4% interest on the $4,000 is $56.

56 x 20 (years) = 1,120

A= $1,120

To get B simply add 1,120 to 4000.

1,120 + 4000 = 5120

B = 5120.

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9x-y= 29 and 9x + y = -29

ahrayia [7]

Answer:

(0,-29) x = 0, y = -29

Step-by-step explanation:

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3 years ago

Read 2 more answers

Please help :( im stuck!!

Ludmilka [50]

Answer:

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Step-by-step explanation:

5 0

3 years ago

What is the answer please help

Goryan [66]

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4 years ago

The indicated function y1(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section

lisabon 2012 [21]

Answer:

$\therefore y_2(x)=-\frac{e^{-6x}}{8}$

The general solution is

$y=c_1e^{2x}-c_2.\frac{e^{-6x}}{8}$

Step-by-step explanation:

Given differential equation is

y''-4y'+4y=0

and $y_1(x)=e^{2x}$

To find the $y_2(x)$ we are applying the following formula,

$y_2(x)=y_1(x)\int \frac{e^{-\int P(x) dx}}{y_1^2(x)} \ dx$

The general form of equation is

y''+P(x)y'+Q(x)y=0

Comparing the general form of the differential equation to the given differential equation,

So, P(x)= - 4

$\therefore y_2(x)=e^{2x}\int \frac{e^{-\int 4dx}}{(e^{2x})^2}dx$

$=e^{2x}\int \frac{e^{-4x}}{e^{4x}}dx$

$=e^{2x}\int e^{-4x-4x} \ dx$

$=e^{2x}\int e^{-8x} \ dx$

$=e^{2x}. \frac{e^{-8x}}{-8}$

$=-\frac{e^{-6x}}{8}$

$\therefore y_2(x)=-\frac{e^{-6x}}{8}$

The general solution is

$y=c_1e^{2x}-c_2.\frac{e^{-6x}}{8}$

4 0

3 years ago

Employees from A and company B receive annual bonuses. What information would you need to test the claim that the difference in

lyudmila [28]

Answer:

1. The required information are

The average annual bonuses, $\bar {x}_1$ received by employees from company A

The average annual bonuses, $\bar {x}_2$ received by employees from company B

The standard deviation, σ₁, of the average annual bonuses for employees from company A

The standard deviation, σ₂, of the average annual bonuses for employees from company A

The number of employees in company A, n₁

The number of employees in company B, n₂

2. The null hypothesis is H₀: $\bar {x}_1$ - $\bar {x}_2$ ≤ 100

The alternative hypothesis is Hₐ: $\bar {x}_1$ - $\bar {x}_2$ > 100

Step-by-step explanation:

1. The required information are

The average annual bonuses, $\bar {x}_1$ received by employees from company A

The average annual bonuses, $\bar {x}_2$ received by employees from company B

The standard deviation, σ₁, of the average annual bonuses for employees from company A

The standard deviation, σ₂, of the average annual bonuses for employees from company A

The number of employees in company A, n₁

The number of employees in company B, n₂

2. The null hypothesis is H₀: $\bar {x}_1$ - $\bar {x}_2$ ≤ 100

The alternative hypothesis is Hₐ: $\bar {x}_1$ - $\bar {x}_2$ > 100

The z value for the hypothesis testing of the difference between two means is given as follows;

$z=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}$

At 0.5 level of significance, the critical $z_\alpha$ = ± 0

The rejection region is z > $z_\alpha$ and z < - $z_\alpha$

Therefore, the value of z obtained from the relation above more than or less than 0, we reject the null hypothesis, and we fail to reject the alternative hypothesis.

7 0

3 years ago