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TiliK225 [7]
3 years ago
6

Two negative integers are five minutes apart on the number line, and their product is 126. What is the sum of the two integers?

Mathematics
1 answer:
kupik [55]3 years ago
7 0
First I will assume that this problem can be reworded as follows:  "<span>Two negative integers are five units apart on the number line."

Let the first (the smaller) negative integer be x and the second y.  Note that y, being bigger than x, can be represented by y=x+5.

First find the 2 integers.  Their product is 126, so x(x+5)=126.
Expanding, x^2 + 5x - 126 = 0.  Using the quadratic formula to solve this, 

          -5 plus or minus sqrt(529)        -5 plus or minus 23
x = --------------------------------------- = -----------------------------
                           2                                              2
                                                                                          -5 -23
We are interested only in negative integers, so take x = ------------
                                                                                               2

Then x = -28/2, or x = -14.  Then y is x+5, or -14+5 = -9.

Check:  does the product of -9 and -14 equal 126, as it must?   YES.</span>
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A is the answer 7th graders are not likely
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Veronika [31]

Answer:

a)1400 + 300x ≤ 5000

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JulsSmile [24]
(x+2)(x+8)(x+k)=x^3+9x^2+6x-16

(x^2+10x+16)(x+k)=x^3+9x^2+6x-16

x^3+10x^2+16x+kx^2+10kx+16k=x^3+9x^2+6x-16

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k(x^2+10x+16)=-x^2-10x-16

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k=-1

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3 years ago
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