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kari74 [83]
3 years ago
6

Question 1 of 5

Mathematics
2 answers:
Zarrin [17]3 years ago
8 0
Answer B: 21/28
The best answer out of those
poizon [28]3 years ago
4 0

Answer:

B

Step-by-step explanation:

21/28 is 0.75 and 12/16 is 0.75 so they are proportional

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When you sample the first individuals you can find, you call it a _____; it's cheap and easy to do, but statistically not a very
ZanzabumX [31]

Answer:

E.

simple random sample

Step-by-step explanation:

Simple random sample: Every member and set of members has an equal chance of being included in the sample. Random samples are usually fairly representative since they don't favor certain members.

3 0
3 years ago
In △ABC, m∠A=39°, a=11, and b=13. Find c to the nearest tenth.
Talja [164]

For this problem, we are going to use the <em>law of sines</em>, which states:

\dfrac{\sin{A}}{a} = \dfrac{\sin{B}}{b} = \dfrac{\sin{C}}{c}


In this case, we have an angle and two sides, and we are trying to look for the third side. First, we have to find the angle which corresponds with the second side, B. Then, we can find the third side. Using the law of sines, we can find:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{B}}{13}


We can use this to solve for B:

13 \cdot \dfrac{\sin{39^{\circ}}}{11} = \sin{B}

B = \sin^{-1}{\Big(13 \cdot \dfrac{\sin{39^{\circ}}}{11}\Big)} \approx 48.1


Now, we can find C:

C = 180^{\circ} - 48.1^{\circ} - 39^{\circ} = 92.9^{\circ}


Using this, we can find c:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{92.9^{\circ}}}{c}

c = \dfrac{11\sin{92.9^{\circ}}}{\sin{39^{\circ}}} \approx \boxed{17.5}


c is approximately 17.5.

8 0
3 years ago
What value added to x^2+2x would complete the square?
svetlana [45]
D is the only one which would make sense :)
7 0
3 years ago
Nancy is 5 years younger than her brother Stan. Last year she was twice as young as he was. How old is each of them now?
otez555 [7]
Nancy: 5 Stan: 10

5 is 5 years
younger then Stan
And 5 is twice as
young as 10
4 0
3 years ago
Read 2 more answers
Consider the trinomial 6x2 + 13x + 6.
attashe74 [19]
In the given expression 6X² + 13X +6, we can easily identify the values of a, b and c. These values are a=6, b=13 and c=6
For the value of "ac", we have:
ac=6*6
ac=36
For a sum of b are 4, we have
ac+b=36+13=49
Therefore, the answer for the last question "The two numbers that have a product of ac and a sum of b are 4 and 9".
8 0
3 years ago
Read 2 more answers
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