The effiency of a machine is
(output work or energy) / (input work or energy) .
For the system described in the question, that's
(123 J) / (150 J) = 0.82 = 82% .
Answer:
50 KeV
Explanation:
50 KeV will be the most likely initial interaction with tissue.
Because Higher the energy lesser will the interaction with tissues, Because it will penetrate through tissue more easily in a very lesser time Whereas the photon with least energy will take more time to penetrate through the tissue, hence, higher interaction with tissue.
Force your doing it purposely and acceleration it’s just happening
