Answer:
yeah I'm Pretty sure it's b
Answer:
3.45×10⁻⁴mm (or 0.000345mm)
Explanation:
Use a method called dimensional analysis here. It involves a chain of conversions, so we'll need some conversions to work with.
- 1nm = 1×10⁻⁹m
- 1mm = 1×10⁻³m
- 345nm; which is given
If you knew the conversion from nanometers to millimeters then you could just do it in one step. But I don't, so I won't. Anyways, you put the conversions into fraction form like so:
And then orient them in a way where multiplying the two (or more in other instances) gives you the units you want. In this cas it's millimeters so you'll have:
(345nm)•(1×10⁻⁹m/1nm)•(1mm/1×10⁻³m)
Notice how all the units reduce except for mm. From here you just multiply across and should get 345×10⁻⁶mm which simplifies to 3.45×10⁻⁴mm.
For finding the orbital speed of the satellite we can say that the centripetal force for the circular motion of satellite is provided by the gravitational force of earth
so here we can say


now we will have

now here we will say that orbital speed of the satellite is inversely depends on the orbital radius
<em>So here if orbital speed is half then as per above relation we can say that orbital distance will become four times</em>
<em>Also we can say that if orbital speed is double then orbital distance will become one fourth of initial distance.</em>
Answer:
the planes times in the air
Explanation:
When a paper airplane is thown the path it takes is not the same every time. So, measuring the distance between the points where the airplane took off and the point where is landed would not show the time the plane was in the air.
The weight also does not determine the time the plane was in the air.
So, the planes air time recorded with the stopwatch gives the time the plane was in the air and will indicate the best plane.
Answer:
Explanation:
The equilibrium equation is:

The initial concentration of A can be calculated from the ideal gas equation:

Determine the conversion of substance A to substance C using an ICE table and the Kc constant:
A ⇄ 3C
I 0.304 0
C - x + 3x
E 0.304 - x 3x

Solve for x:
You need to use a graphing calculator:
Then:

The equilbrium conversion is:
![\% = [0.304mol/liter-0.1845mol/liter]/(0.304mol/liter)\times 100](https://tex.z-dn.net/?f=%5C%25%20%3D%20%5B0.304mol%2Fliter-0.1845mol%2Fliter%5D%2F%280.304mol%2Fliter%29%5Ctimes%20100)
