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sleet_krkn [62]
3 years ago
12

Marx argued that what happens when a worker is separated

Physics
1 answer:
kicyunya [14]3 years ago
3 0

Answer:

well its simple the worker wouldn't actually be working

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Help me with this plzzz
Marysya12 [62]

Answer:

yeah I'm Pretty sure it's b

4 0
3 years ago
Read 2 more answers
345nm=____mm<br>I need to see how to work the problem out​
Amanda [17]

Answer:

3.45×10⁻⁴mm (or 0.000345mm)

Explanation:

Use a method called dimensional analysis here. It involves a chain of conversions, so we'll need some conversions to work with.

  • 1nm = 1×10⁻⁹m
  • 1mm = 1×10⁻³m
  • 345nm; which is given

If you knew the conversion from nanometers to millimeters then you could just do it in one step. But I don't, so I won't. Anyways, you put the conversions into fraction form like so:

  • 1nm/1×10⁻⁹m
  • 1mm/1×10⁻³m

And then orient them in a way where multiplying the two (or more in other instances) gives you the units you want. In this cas it's millimeters so you'll have:

(345nm)•(1×10⁻⁹m/1nm)•(1mm/1×10⁻³m)

Notice how all the units reduce except for mm. From here you just multiply across and should get 345×10⁻⁶mm which simplifies to 3.45×10⁻⁴mm.

3 0
3 years ago
What would happen to a satellite if it’s orbit speed was reduced by half? Also how about if it doubled?
weeeeeb [17]

For finding the orbital speed of the satellite we can say that the centripetal force for the circular motion of satellite is provided by the gravitational force of earth

so here we can say

F_g = \frac{mv^2}{r}

\frac{GMm}{r^2} = \frac{mv^2}{r}

now we will have

v = \sqrt{\frac{GM}{r}}

now here we will say that orbital speed of the satellite is inversely depends on the orbital radius

<em>So here if orbital speed is half then as per above relation we can say that orbital distance will become four times</em>

<em>Also we can say that if orbital speed is double then orbital distance will become one fourth of initial distance.</em>

7 0
3 years ago
Roseanne and Jackie were asked to design and create a paper airplane that would stay in the air for as long as possible. They be
jekas [21]

Answer:

the planes times in the air

Explanation:

When a paper airplane is thown the path it takes is not the same every time. So, measuring the distance between the points where the airplane took off and the point where is landed would not show the time the plane was in the air.

The weight also does not determine the time the plane was in the air.

So, the planes air time recorded with the stopwatch gives the time the plane was in the air and will indicate the best plane.

6 0
3 years ago
Consider the elementary gas-phase reversible reaction A 3C Pure A enters at a temperature of 400 K and a pressure of 10 atm. At
xxMikexx [17]

Answer:

  • 39%

Explanation:

The equilibrium equation is:

          A\rightleftharpoons 3C

The initial concentration of A can be calculated from the ideal gas equation:

                 pV=nRT\\\\n/v=p/(RT)\\\\C_A=\dfrac{10atm}{0.08206(atm-dm^3/K-mol)/times 400K}\\\\C_A=0.304mol/liter

Determine the conversion of substance A to substance C using an ICE table and the Kc constant:

             A               ⇄          3C

I            0.304                        0

C             - x                          + 3x

E          0.304 - x                   3x

         K_c=0.25=\dfrac{(3x)^3}{(0.304-x)}

Solve for x:

You need to use a graphing calculator:

  • 108x³ = 0.304 - x
  • 108x³ + x - 0.304 = 0
  • x ≈ 0.1195 mol/liter

Then:

           C_A=0.304mol/liter-0.1195mol/liter=0.1845mol/liter\\\\C_C=3\times 0.304mol/liter=0.912mol/liter

The equilbrium conversion is:

           \% = [0.304mol/liter-0.1845mol/liter]/(0.304mol/liter)\times 100

           \% \approx 39\%

3 0
3 years ago
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