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djyliett [7]
3 years ago
9

Plzz help me with this

Physics
1 answer:
Ilya [14]3 years ago
4 0

Answer: d

Explanation:

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An automobile travels on a straight road for 42 km at 45 km/h. it then continues in the same direction for another 42 km at 90 k
Nina [5.8K]

Answer:

a) The average velocity is v = (60 km/h ; 0)

b) The average speed is 60 km/h

Explanation:

The velocity is a vector that has a magnitude and direction. The average speed is the distance traveled over time without taking into account the direction of the motion.

a)The average velocity is calculated as the displacement over time:

v = Δx/Δt

where

v = velocity

Δx = final position - initial position = traveled distance relative to the center of the reference system.

Δt = final time - initial time (initial time is usually = 0)

We know that the displacement is 84 km but we do not know the time. It can be calculated from the two parts of the trip.

In part 1:

v = 45 km/h = 42 km / t

t = 0.93 h

In part 2:

v = 90 km/h = 42 km / t

t = 42 km / 90 km/h

t = 0.47 h

The time of travel is 0.47 h + 0.93 h = 1.4 h

The average velocity will be:

v = 84 km / 1.4 h = 60 km/h

Expressed as a vector in a 2-dimension plane:

v = (60 km/h; 0)

b) The average speed is calculated as the distance traveled over time. Note that in this case, the distance is equal to the displacement since the direction of the motion is always in one direction. But if the direction of the second part of the trip would have been the opposite to the direction of the first part, the displacement would have been 0 (final position - initial position = 0, because final position = initial position), then, the average velocity would have been 0. In change, the average speed would have been the distance traveled (84 km, 42 km in one direction and 42 km in the other) over time.

Then:

average speed = 84 km / 1.4 h = 60 km/h

c) see attached figure.    

5 0
3 years ago
Please choose the answer that describes the scientific notation for 5,098,000. 
galben [10]
D. 5.098 x 106 is the correct answer when reduced to the proper notation.
3 0
3 years ago
An object weighing 1.840 kg has a volume of 0.0015 m3. What is the density of the object in g/cm3?
olga_2 [115]

Answer:

1.22gcm³

Explanation:

D = mass/ volume

Mass=1.840kg = 1,840g

1000g = 1kg

1.840kg= x(g)

X(g) = 1.840/1000

= 1840g

Volume = 0.0015m³= 1,500cm³

1m³= 1000,000cm³.

0.0015m³= x(cm³)

X(cm³) = 1000,000×0.0015

X(cm³)= 1500.

Since density is mass/volume, now impute your data's

D=m/v

D=1840/1500

1.22g/cm³

5 0
3 years ago
Ann puts a beaker on the scale which shows the mass to be 1.65kg. The actual mass was 1.72 kg. what was the percent error in Ann
mojhsa [17]

Measured reading is 1.65 kg

actual reading was 1.72 kg

error in the reading is 1.72 - 1.65 = 0.07 kg

Now percentage error is given as

error = \frac{error}{true reading}*100

error = \frac{0.07}{1.72}*100

error = 4.1

<em>so this is -4.1% error as the measured reading is less than the actual value</em>

8 0
3 years ago
What is the resistance ofa wire made of a material with resistivity of 3.2 x 10^-8 Ω.m if its length is 2.5 m and its diameter i
Katarina [22]

R = 0.407Ω.

The resistance  R of a particular conductor is related to the resistivity ρ of the material by  the equation R = ρL/A, where ρ is the material resistivity, L is the length of the material and A is the cross-sectional area of ​​the material.

To calculate the resistance R of a wire made of a material with resistivity of 3.2x10⁻⁸Ω.m, the length of the wire is 2.5m and its diameter is 0.50mm.

We have to use the equation R = ρL/A but first we have to calculate the cross-sectional area of the wire which is a circle. So, the area of a circle is given by A = πr², with r = d/2. The cross-sectional area of the wire is A = πd²/4.  Then:

R =[(3.2x10⁻⁸Ω.m)(2.5m)]/[π(0.5x10⁻³m)²/4]

R = 8x10⁻⁸Ω.m²/1.96x10⁻⁷m²

R = 0.407Ω

5 0
3 years ago
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