Plzz help me with this

Block 1, of mass m1 = 3.90 kg , moves along a frictionless air track with speed v1 = 31.0 m/s . It collides with block 2, of mas

Nostrana [21]

The energy would remain equal to that of the initial kinetic energy since it is a frictionless surface. However if it is an inelastic collision then energy would be lost due to sound and heat.

7 0

3 years ago

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When a certain amount of heat is supplied to 1KG of insulated aluminium. The temperature of the aluminium rises by 1°C

Bumek [7]

Answer:

The specific heat of aluminium is 897J/kg k . This values is almost 2.3 times of specific heat of copper .

Aluminium has higher thermal capacity than water

Explanation:

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6 0

3 years ago

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A certain brand of hot-dog cooker works by applying a potential difference of 120 V across opposite ends of a hot dog and allowi

ivanzaharov [21]

Answer:

The time it will take to cook three hot dogs simultaneously is 2.5 minutes

Explanation:

Here we have, the Energy of electric heating given by Joule heating that is;

P = IV = 120×10 = 1200 J/s = 1.2 kJ/s

Since the energy required to cook one hotdog = 60.0 kJ we have

Energy required to cook three hot dogs = 3 × 60.0 kJ = 180.0 kJ

Therefore, the time required to cook the three hot dogs is

(180.0 kJ)/(1.2 kJ/s) = 150 s

The time it takes to cook three hot dogs simultaneously is

150 seconds or 150/60 minutes which is 2 minutes 30 seconds or 2.5 minutes

5 0

3 years ago

1. What is the momentum of a 0.15 kg arrow that is traveling at 120 m/s?

Korvikt [17]

For this case we have that by definition, the momentum equation is given by:

$p = m * v$

Where:

m: It is the mass

v: It is the velocity

According to the data we have:

$m = 0.15 \ kg\\v = 120 \frac {m} {s}$

Substituting:

$p = 0.15 * 120\\p = 18 \frac {kg * m} {s}$

On the other hand, if we clear the variable "mass" we have:

$m = \frac {p} {v}$

According to the data we have:

$p = 250 \frac {kg * m} {s}\\v = 5 \frac {m} {s}\\m = \frac {250} {5}\\m = 50 \ kg$

Thus, the mass is $50 \ kg$

Answer:

$p = 18 \frac {kg * m} {s}\\m = 50 \ kg$

3 0

3 years ago

Sound waves are longitudinal waves that can travel through air. Would you expect sound waves to travel faster through a low-dens

Serjik [45]

Answer:

Sound waves travel faster in a low-density gas

Explanation:

First of all, let's remind that sound waves are pressure waves: they consist of oscillations of the particles in a medium, which oscillate back and forth along the direction of motion of the wave (longitudinal wave).

The speed of sound in an ideal gas is given by the equation

$v=\sqrt{\gamma \frac{p}{\rho}}$

where

$\gamma$ is the adiabatic index of the gas

p is the gas pressure

$\rho$ is the gas density

From the equation, we see that the speed of sound is inversely proportional to the square root of the density: therefore, the lower the density, the faster the sound waves.

So, sound waves will travel faster in a low-density gas.

6 0

3 years ago