Answer:
I am certain the answer is A sorry if im wrong
Explanation:
Answer:
No, the child cannot inherit the disease.
Explanation:
The problem tells you that the man has a recessive allele for an inherited disease, but he has a normal phenotype. This means that the disease is recessive and in order for an individual to have the disease, they must have two recessive copies of the allele. The problem also tells you that the mother has a genotype that does not include this allele. With this information, you can do a punnet cross of BB (mother) x Bb (carrier father), and end up with the following possible genotypes: BB, Bb, BB, Bb. Therefore the child will not have the disease, but there is a 50% chance that the child will be a carrier for the disease.
Answer:
B. 100 percent yellow seeds
Explanation:
When a gene has two alleles and one allele is dominant over the other, the dominant allele is expressed in the heterozygous state and the expression of the recessive allele is masked. According to the given information, the allele for yellow seed color is dominant over the allele for the green seed color.
Let's assume that the allele "Y" gives yellow color to the seeds while the allele "y" is responsible for green seed color. A cross between two pure breeding yellow seeded (YY) and green seeded (yy) plants would produce all the yellow seeded progeny with genotype "Yy".
YY (Yellow) x yy (green) = Yy (yellow)
Explanation:
the light energy is converted to heat energy in order to break the covalent bonds in the water molecules that are combined with CO2 to create glucose
The abbreviation for adenosine triphosphate is ATP
