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OleMash [197]
3 years ago
6

Two different substances, Substance A and Substance B, are in direct contact with each other and are at different temperatures.

The particles in Substance B are vibratingthe particles in Substance A. This means Substance B isSubstance A and conduction will.
Physics
2 answers:
Alenkinab [10]3 years ago
8 0

Answer:

resonance

Explanation:

The particles of substance B will cause the particle of substance A to vibrate at the same frequency

Arlecino [84]3 years ago
3 0

Answer:

The first answer is faster than and the second answer is warmer than.

The third answer is C. occur from Substance B to Substance A.

Explanation:

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As 390-g of hot milk cools in a mug, it transfers 30,000 J of heat to the environment.
stiks02 [169]
Q = m.s.Δt
Δt = Q /m.s
Here, Q = 30,000 J
m = 390 g
s = 3.9 J/g C

Substitute their values, 
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 = 30,000 / 1521
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In short, Your Answer would be Option D

Hope this helps!

7 0
3 years ago
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A disk-shaped platform has a known rotational inertia. The platform is mounted on a fixed axle and rotates in a horizontal plane
Nataly [62]

The frictional torque exerted on the platform by the axle as the platform rotates will be;

\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]

<h3>What is torque?</h3>

Torque is the force's twisting action about the axis of rotation. Torque is the term used to describe the instant of force. It is the rotational equivalent of force. Torque is a force that acts in a turn or twist.

The amount of torque is equal to force multiplied by the perpendicular distance between the point of application of force and the axis of rotation.

Work done by the frictional torque = Change in the rotational kinetic energy of the wheel

\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]

Where,

\rm T_f is the frictional torque

\rm \omega is the final angular velocity

\rm  \omega_0 is the initial angular velocity

\rm \theta is the angular displacement

Hence, the frictional torque exerted on the platform by the axle as the platform rotates will be;

\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]

To learn more about the torque, refer to the link;

brainly.com/question/6855614

#SPJ1

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2 years ago
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Degger [83]
Hi, thank you for posting your question here at Brainly.

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