Answer:
<h2>92.86 kg </h2>Explanation:
lThe mass of an object given only it's force and acceleration can be found by using the formula
f is the force
a is the acceleration
From the question
f = 195 N
a = 2.1 m/s
We have
We have the final answer as
<h3>92.86 kg</h3>Hope this helps you
Answer:
4 x 10⁷m/s
Explanation:
When a charged particle moves in a curved path in a magnetic field, it experiences some magnetic force, and in the absence of any other force, which supplies the centripetal force needed to keep the particle in balance.
Let the magnetic force be
Let the centripetal force be
=> =
--------------(i)
We know that;
= qvBsinθ
Where;
q = charge on the particle
v = speed of the particle
B = magnetic field intensity
θ = angle between the speed and magnetic field vectors
Also;
=
Where;
m = mass of the particle
v = velocity/speed of the particle
r = radius of the circular path of motion.
From equation (i)
qvBsinθ = [divide both sides by v]
qBsinθ = [make v subject of the formula]
v = qrBsinθ / m --------------------(ii)
From the question;
B = 1.0T
r = 0.4m
θ = 90° [since magnetic field is always perpendicular to velocity]
q = 1.6 x 10⁻¹⁹C [charge of a proton]
m = 1.6 x 10⁻²⁷kg [mass of a proton]
Substitute these values into equation(ii) as follows;
v = (1.6 x 10⁻¹⁹ x 0.4 x 1.0 x sin90°) / (1.6 x 10⁻²⁷)
v = 4 x 10⁷ m/s
Therefore the speed of the proton is 4 x 10⁷m/s
Answer:
Acceleration of the car is .
Explanation:
It is given that,
Initial speed of the car, u = 29 m/s
Finally it reaches a speed of, v = 34 m/s
Distance, d = 110 m
We need to find the acceleration of the car as it speed up. It can be calculated using third law of motion as :
So, the acceleration of the car as it speeds up is . Hence, this is the required solution.