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eimsori [14]
4 years ago
12

A gas with a volume of 535 mL at a temperature of -25C is heated to 175C. What is the new volume of the gas if pressure and numb

er of moles are held constant?
Chemistry
2 answers:
Paul [167]4 years ago
6 0

Answer:

The new volume of the gas is 966 mL

Explanation:

Step 1: Data given

Volume = 535 mL

Initial temperature = -25.0 °C

Final temperature = 175 °C

Step 2: Calculate the new volume

V1/T1 = V2/T2

⇒with V1 = the initial volume = 535 mL = 0.535 L

⇒with T1 = -25 °C = 248 K

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the new temperature = 175 °C = 448K

0.535 L/ 248 K = V2 / 448K

V2 = 0.966 L =966 mL

The new volume of the gas is 966 mL

MakcuM [25]4 years ago
5 0

Answer:966.45ml

Explanation:

Using Charles law.. V1/T1=V2/T2

V1=535ml

T1=-25+273

=248k

T2= 175+273=448k

V2=?

V2= V1*T2/T1

V2=535*448/248

V2=239680/248

V2=966.45ml

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Bas_tet [7]
I just need more points that's why I'm doing this
8 0
3 years ago
How many atoms are in 766.3 grams of Li?
34kurt

1 mol of any substance is made of 6.022 x 10²³ units, these units could be atoms making up elements or molecules making up a compound.

In this case. 1 mol of Li is made of 6.022 x 10²³ atoms of Li

The molar mass of Li is 6.94 g/mol

Therefore mass of 1 mol of Li is 6.94 g

In 6.94 g of Li there are - 6.022 x 10²³ atoms

Then in 766.3 g of Li there are - 6.022 x 10²³ atoms / 6.94 g x 766.3 g = 665 x 10²³

There are 6.65 x 10^25 atoms of Li

6 0
4 years ago
8. An elevator is moving upward with a speed of 11 m/s. Three
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Answer:

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3 0
3 years ago
Question 5
seropon [69]

Answer:

0.128 g

Explanation:

Given data:

Volume of gas = 146.7 cm³

Pressure of gas = 106.5 Kpa

Temperature of gas = 167°C

Mass of oxygen gas = ?

Solution:

Volume of gas = 146.7 cm³ (146.7 /1000 = 0.1467 L)

Pressure of gas = 106.5 Kpa (106.5/101 = 1.1 atm)

Temperature of gas = 167°C (167 +273.15 = 440.15 K)

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

n = PV/RT

n = 1.1 atm× 0.1467 L / 0.0821 atm.L/ mol.K   × 440.15 K

n = 0.1614 / 36.14 /mol

n = 0.004 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 0.004 mol × 32 g/mol

Mass = 0.128 g

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3 years ago
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