The oxidation state is zero for Fe (s)
The 3rd diagram is a mixture because it has 2 substances
AgF consists of Ag+ and F- ions, which are fully dissociated in aqueous solution. When solving electrolysis problems, it is important to remember that water itself may also be a subject to electrolysis. Therefore, determining which species is oxidized and which species is reduced depends on selecting the processes that are the most energetically favorable. The most preferred reduction reaction will be Ag+ + e- = Ag (Emf=0.7996 V) which will occur at the cathode, on the other hand, the most favorable oxidation reaction will be
2H2O = O2 +4H+ + 4e- (Emf = -1.3 V) that will occur at the anode. Thus, the product at the anode is oxygen gas and at the cathode electrode is silver metal.
Therefore the largest atoms are on the left and the smallest on the right. So sodium (Na) has the largest atomic radius, as the valence electrons are the least attracted to the nucleus
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Mass =?
moles of N2 = 4.25 x 103 mol
molar mass of N2 = (14)x2 = 28