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mrs_skeptik [129]
3 years ago
11

Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici

ent is "1".
NH3 + F2 → N2F4 + HF
Chemistry
2 answers:
Sveta_85 [38]3 years ago
8 0
2 NH3 + 5F2 = blank N2F4 + 6 HF
erica [24]3 years ago
3 0

Answer : The balanced chemical reaction will be,

2NH_3+5F_2\rightarrow N_2F_4+6HF

Explanation :

Balanced chemical reaction : It is defined as the chemical reaction in which the number of individual atoms of an element in reactant side always be equal to the number of individual atoms of an element in product side.

The given balanced reaction will be,

2NH_3+5F_2\rightarrow N_2F_4+6HF

By the stoichiometry we can say that, 2 moles of NH_3 react with 5 moles of F_2 to give 1 mole of N_2F_4 and 6 moles of HF as a product.

Hence, the balanced chemical reaction will be,

2NH_3+5F_2\rightarrow N_2F_4+6HF

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A helium-filled balloon has a volume of 2.48 L and a pressure of 150 kPa. The volume of the balloon increases to 2.98 L after yo
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Answer:

THE NEW PRESSURE OF THE HELIUM GAS AT 2.98 L VOLUME IS 124.8 kPa.

AT AN INCREASE ALTITUDE, THERE IS A LOWER PRESSURE ENVIRONMENT AND THE HELIUM GAS PRESSURE DECREASES AND HENCE AN INCREASE IN VOLUME.

Explanation:

The question above follows Boyle's law of the gas law as the temperature is kept constant.

Boyle's law states that the pressure of a fixed mass of gas is inversely proportional to the volume, provided the temperature remains constant.

Mathematically, P1 V1 = P2 V2

P1 = 150 kPa = 150 *10^3 Pa

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Rearranging the equation, we obtain;

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Pls tell me how to solve this!
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Answer:

12 seconds

Explanation:

Time taken by 50cm³ of oxygen to diffuse from pinhole

= 1 minute = 60 seconds

⠀

⠀

\textsf{ Rate of oxygen} \sf (O_2) = \frac{50}{60}

⠀

⠀

⠀

<u>Let</u><u> </u><u>time</u><u> </u><u>taken</u><u> </u><u>by</u><u> </u><u>5</u><u>0</u><u>c</u><u>m</u><u>³</u><u> </u><u>of</u><u> </u><u>hydrogen</u><u> </u><u>to</u><u> </u><u>diffuse</u><u> </u><u>from</u><u> </u><u>pinhole</u><u> </u><u>=</u><u> </u><u>t</u><u> </u><u>seconds</u>

⠀

⠀

\textsf {Rate of hydrogen } \sf(H_2) =  \frac{50}{t}

⠀

⠀

⠀

According to the formula

\sf \frac{Rate  \: of  \: hydrogen(H_2)}{Rate \:  of \:  oxygen(O_2) }  =   \sqrt{ \frac{Molar \: mass \: of \:  O_2}{Molar  \: mass \: of \: H_2} }

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\large  \sf  \frac{50}{t}  \div  \frac{50}{60}  =  \sqrt{ \frac{\cancel{32}\small 16}{\cancel2} }  \\  \\  \sf   \large \frac{ \cancel{50}}{t}  \times  \frac{60}{ \cancel{50}}  =  \sqrt{16}  \\  \\  \sf   \large \frac{60}{t}  = 4 \\  \\  \sf \large  \frac{ \cancel{60} \:  \small12}{ \cancel4}  = t \\  \\    \large \underline{ \boxed{ \tt t = 12 \: seconds}}

⠀

⠀

⠀

<h3><u>Henceforth</u><u>,</u><u> </u><u>the</u><u> </u><u>time</u><u> </u><u>taken</u><u> </u><u>by</u><u> </u><u>5</u><u>0</u><u>c</u><u>m</u><u>³</u><u> </u><u>of</u><u> </u><u>hydrogen</u><u> </u><u>to</u><u> </u><u>diffuse</u><u> </u><u>is</u><u> </u><u>1</u><u>2</u><u> </u><u>seconds</u><u>.</u><u> </u></h3>

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<h2>Thank you!</h2>
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